Answer:D) peek
Explanation:Peek operation or function is the method that is used for the returning of the values on the front of the queue or stack type datatypes. This operation function over those datatypes having group or collection of the elements and does not eliminate any element from the queue.
NOsuchElemnet exception is shown when there is the peek operation in the queue for the element to be displayed on the top and no deletion can take place .Thus, the correct option is option(D).
Answer:
If its any easy question, answer it yourself.
Explanation:
:)
Since Betty is applying for a software analyst role, she should specialize in INFORMATION TECHNOLOGY.
<span>Information technology or IT is defined as the study or use of systems in computers and telecommunications for storing, retrieving, and sending information.
</span>
Betty's role as a software analyst would be to:
1) <span> study the </span>software<span> application domain,
2) prepare </span>software<span> requirements and specification (</span>Software<span> Requirements Specification) documents.
3) be the link between the software users and software developers.</span>
Answer: <u>Computer hardware is any physical device used in or with your machine, like for example, a mouse, or a keyboard.</u> Computer software is a collection of programming code installed on your computer's hard drive it can process billions of data and inputs through this.
Hope this helps!
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
