Question

Solve 0 = 4x2 12x 9. select the equation that shows the correct substitution of a, b, and c in the quadratic formula.

Answer 1

We get the value of x as - 3 / 2 and the quadratic equation is represented by a x² + b x + c= 0.

We know that the formula for quadratic equation is given by:

a x² + b x + c= 0

Here, we have the quadratic equation as:

4x² + 12 x + 9 = 0

We will solve it by using middle term splitting.

We can write the equation as:

4 x² + 6 x + 6 x + 9 = 0

Taking common factors:

2 x ( 2 x + 3) + 3 ( 2 x + 3) = 0

Again taking the common factors:

(2 x + 3)(2 x + 3) = 0

Solving it to get the value of x:

x = - 3 / 2 and - 3 / 2.

Therefore, we get the value of x as - 3 / 2 and the quadratic equation is represented by a x² + b x + c= 0.

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Answer 2

Answer:

Solve 0 = 4x2 + 12x + 9. select the equation that shows the correct substitution of a, b, and c in the quadratic formula.

We know that quadratic equation for:

ax^2 + bx + c= 0…………(1) is

X = {- b + - √( b^2 -4ac) } / 2a ……….(2)

for calculating the value of x. where a, b and c values are given in numeric.

So , here if we compare the value of 0 = 4x^2 + 12x + 9 with equation no 1 then we can get

a = 4 , b= 12 and c = 9

So from these we can get

X = {- 12 + - √(12^2 – 4*4*9)} / 2*4

X = {- 12 + - √(12*12 – 4*4*9) } / 2*4

X = - 12 + - (√144 – 144) / 2*4

X = - 12 + 0 /8

X= - 3/2

So the implemented equation of 0 = 4x^2 + 12x + 9. Will be X ={ - 12 + - √(12*12 – 4*4*9 )/ 2*4} and the calculated value of x will be -3/2

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