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boyakko [2]
2 years ago
8

Raphi buys 1 rubber and 1 pen for £1.25.

Mathematics
1 answer:
Maslowich2 years ago
5 0

Answer:

Step-by-step explanation:

Cost of one rubber = $1

Cost of one pen = 0.25

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Geomtry plzzzzz help. me
Andre45 [30]

Answer:

N=3.5

Step-by-step explanation:

it is 3.5 because it said line p is the perendicular bisector so the triangle has to be equal. so the line ZY=XY

14/4=3.5

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3 years ago
What is the square root of 124 rounded to the nearest hundredths?
polet [3.4K]
The actual square root of 124 is 11.1355287257. Rounded to the nearest hundredth would be 11.14
8 0
3 years ago
Can anybody help please?
Helen [10]

Answer:

AB = 24 cm, BC = 6 cm

Step-by-step explanation:

The perimeter of PQRS = 2(8) + 2(2) = 16 + 4 = 20 cm

Given the perimeter of ABCD is 60 cm, then

scale factor = \frac{60}{20} = 3

That is the dimensions of ABCD are 3 times those of PQRS, so

AB = 3 × 8 cm = 24 cm

BC = 3 × 2 cm = 6 cm

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3 years ago
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natta225 [31]

3  is the answer

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3 years ago
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Given right triangle ABC, with altitude CD intersecting AB at point D. If AD = 5 and DB = 8, find the length of CD, in simplest
galben [10]

First we dra a triangle:

To prove that the triangles are similar we have to do the following:

Considet triangles ABC and ACD, in this case we notice that angles ACB and ADC are equal to 90°, hence they are congruent. Furthermore angles CAD and CAB are also congruent, this means that the remaining angle in both triangles will also be congruent, therefore by the AA postulate for similarity we conclude that:

\Delta ABC\approx\Delta ACD

Now consider triangles ABC and BCD, in this case we notice that angles ACB and BDC are congruent since they are both equal to 90°. Furthermore angles ABC and DBC are also congruent, this means that the remaining angle in both triangles will, once again, be congruent. Hence by the AA postulate we conclude that:

\Delta ABC\approx\Delta BCD

With this we conclude that traingles BCD and ACD are both similar to triangle ABC, and by the transitivity property of similarity we conclude that:

\Delta ACD\approx BCD

Now that we know that both triangles are similar we can use the following proportion:

\frac{h}{x}=\frac{y}{h}

this comes from the fact that the ratios should be the same in similar triangles.

From this equation we can find h:

\begin{gathered} \frac{h}{x}=\frac{y}{h} \\ h^2=xy \\ h=\sqrt[]{xy} \end{gathered}

Plugging the values we have for x and y we have that h (that is the segment CD) has length:

\begin{gathered} h=\sqrt[]{8\cdot5} \\ =\sqrt[]{40} \\ =\sqrt[]{4\cdot10} \\ =2\sqrt[]{10} \end{gathered}

Therefore, the length of segment CD is:

CD=2\sqrt[]{10}

6 0
2 years ago
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