If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Answer:
Evaluate ∫3x2sin(x3)cos(x3)dx
Step-by-step explanation:
hello (a) using the substitution u=sin(x3) because
du =3x²(cos x3)dx
you have ∫3x2sin(x3)cos(x3)dx = ∫udu=u²/2 +c............continu
6:18 students in Debra's class own a cellphone. Because there are 24 people in total. Minus the people who already own cellphones. Leaving 18 without cellphones. The ratio is people who have cellphones to people who do not.
24-6=18. Thus, the ratio would be 6:18
3. 5x5x5. i am not sure if i am correct but i am assuming it is that.
