Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Answer:
3(9e + 8)
Step-by-step explanation:
the highest common factor is 3 so factor it out.
The answer is permutation. It is <span>the action of changing the arrangement, especially the linear order, of a set of items.
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Answer:
257
General Formulas and Concepts:
Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Define</u>
2x² + 5x + 7
x = 10
<u>Step 2: Evaluate</u>
- Substitute: 2(10)² + 5(10) + 7
- Exponents: 2(100) + 5(10) + 7
- Multiply: 200 + 50 + 7
- Add: 250 + 7
- Add: 257