Answer:
question 9
= –12
while question 11=, x= –72
Step-by-step explanation:
question 9=
u= –16+4= –12
question 11=
cross multiplication
x = -36 multiplied by 2 =
-72
I HOPE THIS HELPED IF WRONG IM SORRY
Answer:
$5.66/gal
Step-by-step explanation:
To calculate the current price of gas, multiply $4.35/gal by (1 + 0.30), or by 1.30:
1.30($4.35/gal) = $5.66/gal
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
Answer:
$234
Step-by-step explanation:
Create a proportion where x is the amount he gets working 36 hours
= 
Cross multiply and solve for x
48x = 11232
x = 234
So, when he works 36 hours a week, he will get paid $234
Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
To Learn more about similar flagpole questions:
brainly.com/question/14277535
#SPJ4
