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OLga [1]
2 years ago
9

What is the Composite Surface Area?​ Need help asap is due today.

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
4 0
I’m really not sure but 216 because bass multiplied by height multiplied by width (6*6*6)
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Based on a​ poll, among adults who regret getting​ tattoos, 12​% say that they were too young when they got their tattoos. Assum
Tema [17]

Answer:

a.  0.6588

b. 0.3978

c. 0. 279

Step-by-step explanation:

In the given question the success and failure are given the number of outcomes is fixed so binomial distribution can be applied.

Here success=  p = 12 % or 12/100 = 0.12

failure = q= 1-p = 1-0.12 = 0.88

n= 10

Using binomial probability distribution

a. Probability that the number of selected adults saying they were too young is 0 or 1 is calculated as:

P (x=0,1) = 0.12 ⁰(0.88)¹⁰10 C0  + 0.12 (0.88)⁹ 10 C1=  1* 0.279 * 1  + 0.12 ( 0.3165) 10 =  0. 279 + 0.3978=  0.6588

b. Probability that exactly one of the selected adults says that he or she was too young to get tattoos is calculated as

P (x=1) =  0.12 (0.88)⁹ 10 C1=  0.12 ( 0.3165) 10 =  0.3978

c. Probability that none of the selected adults say that they were too young to get tattoos is

P (x=0) = 0.12 ⁰(0.88)¹⁰10 C0  =  1* 0.279 * 1   =  0. 279

4 0
3 years ago
Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and
Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates (x_A,y_A)

Vectors AB and AB' are perpendicular, then

\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0

Vectors AC and AC' are perpendicular, then

\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0

Now, solve the system of two equations:

\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.

Subtract these two equations:

5x_A-y_A-8=0\Rightarrow y_A=5x_A-8

Substitute it into the first equation:

x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2

Then

y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0
3 years ago
HELP!
Readme [11.4K]

Answer: You have a better chance if you do not replace the red marble.

Step-by-step explanation:

The bag has:

5 red marbles

8 blue marbles

4 yellow marbles

3 green marbles

A total of 5 + 8 + 4 + 3 = 20

You want to draw a red marble and then a blue marble.

The probability of drawing a red marble in your first attempt is the number of red marbles divided the total number of marbles:

P1 = 5/20  

now you want to draw a blue marble.

If you replace the red marble, you have 20 marbles again in the bag, then the probability of drawing a blue marble is:

P2 = 8/20

The joint probability is P = P1*P2 = (5/20)*(8/20) = 0.1

If you do not replace the red marble, you have 19 total marbles in the bag, then the probability of taking a blue marble is:

P2 = 8/19

The joint probability is:

P = P1*P2 = (5/20)*(8/19) = 0.105

The probability is slightly bigger if you do not replace the red marble.

7 0
3 years ago
Read 2 more answers
Problem Page Jessica's boat has a top speed of 6 miles per hour in still water. While traveling on a river at top speed, she wen
stealth61 [152]
I think it is 3:1 so tell me if it is wrong
6 0
3 years ago
A composition of transformations maps pre-image EFGH to final image E"F"G"H".
lubasha [3.4K]

Answer:

a translation down and left :)

Step-by-step explanation:

8 0
2 years ago
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