We are to find the Probability the someone buys a book that is paperback and fiction.
Let P(F) represents the event that the book is fiction and P(P) represents the event that the book is paperback. We are to find P(F∩P)
P(F∩P) = P(F) x P(P)
From the tree diagram we can see that:
P(F) = 0.45
P(P) = 0.65
Using the values, we get:
P(F∩P) = 0.45 x 0.65 = 0.2925
So, the Probability the someone buys a book that is paperback and fiction is 0.2925.
So, option B gives the correct answer
Answer: Andrew = 90 pounds
Explanation:
Assume Andrew weight is X
Since Jackson weight is 3 times Andrew
Then it’s 3x
3x + x = 360
4x = 360
x = 90
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Π=3.14
Let's start with two digits:
3.14 = 3 14/100
= 3 7/50
= 157/50
would be the approximation for that. Let's add a few more digits:
3.1415 = 3 1415/10000
= 3 283/2000
= 6283/2000
