Question

The equation of the line is 3y+2x=12 . what is the slope of the line perpendicular to this equation?

Answer 1

The slope
$\frac{3}{2}$

Answer 2

Hey there! :)

3y + 2x = 12

To find the slope of this equation, we must turn this into slope-intercept form. Slope-intercept form is very simply : y = mx + b ; where m = slope, b = y-intercept.

Our first step should be to subtract 2x from both sides.

3y + 2x - 2x = 12 - 2x

Simplify.

3y = -2x + 12

Then, divide both sides by 3 so that we could get y by itself (which is what we call isolated in the math world).

3y ÷ 3 = (-2x + 12) ÷ 3

Simplify.

y = -2/3x + 4

So, our slope is -2/3!

~hope I helped~