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3 years ago

Solve for x. 3x−1=9x+2 Enter your answer in the box. x =

Mathematics

2 answers:

gulaghasi [49]3 years ago

6 0

Answer:

Its ACTUALLY -5

Step-by-step explanation:

Look at the attachment

julia-pushkina [17]3 years ago

3 0

Answer:

x= -1

Step-by-step explanation:

3x-1=2x2 (calculate the product)

3x-1=4x (move terms)

3 x - 4 x =1 (collect the terms)

- x = 1 (change the signs)

Solution is x = -1

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3. In 2014, a small town had a population of 27,000 people. Since 2014, the town

WITCHER [35]

Answer:

38,340

Step-by-step explanation:

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Vlad1618 [11]

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Agata [3.3K]

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3 years ago

(1+tanx)/(sinx+cosx)=secx

jek_recluse [69]

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ is proved

<h3><u>Solution:</u></h3>

Given that,

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ ------- (1)

First we will simplify the LHS and then compare it with RHS

$\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}$ ------ (2)

$\text {We know that } \tan x=\frac{\sin x}{\cos x}$

Substitute this in eqn (2)

$=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}$

On simplification we get,

$=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}$

$=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}$

Cancelling the common terms (sinx + cosx)

$=\frac{1}{c o s x}$

We know secant is inverse of cosine

$=\sec x=R . H . S$

Thus L.H.S = R.H.S

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$

Hence proved

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3 years ago