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sp2606 [1]
2 years ago
5

What is the route of non-fat nutrients from the small intestine to their release as nutrients to the body?

Biology
1 answer:
miv72 [106K]2 years ago
6 0

The route of non-fat nutrients from the small intestine to their release as nutrients to the body can vary depending upon the type of nutrient. They can be transported either by passive or active transporters, or through blood stream, or may be absorbed by water.

Small intestine is a part of the digestive system. Its function is to digest the various food components, specially fats and proteins. Small intestine is a very large tube-like structure that is fit compactly surrounded by the large intestine.

Nutrients are components present inside food that are required for the growth and strength of the body, They provide several benefits like body-building capacity, immunity from diseases, proper functioning, etc.

To know more about nutrients, here

brainly.com/question/28111967

#SPJ4

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A part of the Calvin cycle has been removed from the diagram on the right. What occurs at this stage of the cycle? Carbon fixati
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Explanation:

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-<br> Calculate the molar mass of a gas that has a density of 1.55g/L.
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Answer: 39.86 g/mol

Explanation:

Assuming this gas is at a pressure of 0.99 atm and a temperature of 37 \°C+273.15=310.15 K, we can solve this problem with the Ideal Gas Law equation:

P.V=n.R.T  (1)

Where:  

P=0.99 atm is the pressure of the gas  

V is the volume of the gas  

n the number of moles of gas  

R=0.0821 \frac{atm.L}{mol.K} is the gas constant  

T=310.15 K is the absolute temperature of the gas in Kelvin

On the other hand, we know the density \rho=1.55 g/L is given by a relation between the mass m and the volume V:

\rho=\frac{m}{V} (2)

Then, the mass is:

m=\rho V (3)

Another important fact here is that the molar mass M_{mass} of an element is given by a relation between the mass of that element and the number of moles n it contains:

M_{mass}=\frac{m}{n} (4)

Isolating n:

n=\frac{m}{M_{mass}} (5)

Substituting (5) in (1):

P.V=\frac{m}{M_{mass}}.R.T  (6)

Substituting (3) in (6):

P.V=\frac{\rho V}{M_{mass}}.R.T  (7)

Isolating M_{mass}:

M_{mass}=\frac{\rho V}{PV}RT (8)

Simplifying:

M_{mass}=\frac{\rho}{P}RT (9)

Solving with the given data:

M_{mass}=\frac{1.55 g/L}{0.99 atm}(0.0821 \frac{atm.L}{mol.K})(310.15 K) (10)

Finally:

M_{mass}=39.86 g/mol This is the molar mass of the gas

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