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fenix001 [56]
2 years ago
12

a wheel with a radius of 45.0 cm rolls without slipping along a horizontal floor (fig. 3-37). at time t 1 ​ the dot p painted on

the rim of the wheel is at the point of contact between the wheel and the floor. at a later time t 2 ​ the wheels has rolled through one-half of a revolution. what are (a) the magnitude and (b) the angle (relative to the floor) of the displacement of p?
Physics
1 answer:
Whitepunk [10]2 years ago
4 0

The magnitude is 167.6cm and the angle (relative to the floor) of the displacement of p is 32.5 degree.

<h3>What is displacement ?</h3>

A displacement is a vector in geometry and mechanics that has a length equal to the shortest distance between a point P's initial and final positions. It calculates the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement.

A point's ultimate location in relation to its original position, or a displacement, can also be defined as a relative position. The instantaneous velocity of an object is the rate at which the displacement changes as a function of time when studying motions of objects throughout time.

Explanation:

a)

height = 2*r =2*45 cm = 90 cm

y = 1/2 * circumference

   =1/2 * 2*pi*r

   = pi*r

  = pi*45

  = 141.4 cm

displacement  =sqrt ( height^2 + y^2)

   = sqrt (90^2 + 141.4^2)

   = 167.6 cm

Answer: 167.6 cm

b)

angle ,x = atan (height/y)

               = atan (90/141.4)

                = 32.5 degree

Answer: 32.5 degree

To learn more about displacement ,visit:

brainly.com/question/11934397

#SPJ4

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The acrylic plastic rod is 200 mm long and 15 mm in diameter. if an axial load of 300 n is applied to it, determine the change i
Marta_Voda [28]
<span>The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change in its length and the change in its diameter.
   . latd = -0.0002515 (15) = -0.00377 mm
 elat = -Velong = -0.4(0.0006288) = -0.0002515
 d = elong L = 0.0006288 (200) = 0.126 mm
 elong = s
 E = 1.697(106
 )
 2.70(109
 ) = 0.0006288
 s = P
 A = 300 p
 4 (0.015)2 = 1.697 MPa
 â€˘3–25. T</span>
3 0
3 years ago
A large rocket has a mass of 2.00×10⁶ kg at takeoff, and its engines produce a thrust of 3.50×10⁷ N. Find its initial accelerati
Kazeer [188]

Answer:

17.5 m/s²

1.90476 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{3.5\times 10^7}{2\times 10^6}\\\Rightarrow a=17.5\ m/s^2

Initial acceleration of the rocket is 17.5 m/s²

v=u+at\\\Rightarrow \frac{120}{3.6}=0+17.5t\\\Rightarrow t=\frac{\frac{120}{3.6}}{17.5}=1.90476\ s

Time taken by the rocket to reach 120 km/h is 1.90476 seconds

Change in the velocity of a rocket is given by the Tsiolkovsky rocket equation

\Delta v=v_{e}\ln \frac{m_0}{m_f}

where,

m_0 = Initial mass of rocket with fuel

m_f = Final mass of rocket without fuel

v_e = Exhaust gas velocity

Hence, the change in velocity increases as the mass decreases which changes the acceleration

4 0
3 years ago
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

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3 0
2 years ago
A proton, traveling with a velocity of 4.6 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.0
Kobotan [32]

Answer:

B = 0.0815 T

since the direction of force is along south so the magnetic field must be upwards

Explanation:

Force on moving charge in magnetic field is given as

F = q(\vec v \times \vec B)

here we know this is force on proton

so we have

q = 1.6 \times 10^{-19} C

F = 6.0 \times 10^{-14} (-\hat j) N

also we know that the velocity of charge is

v = 4.6 \times 10^6 \hat i m/s

now from above formula we have

(6.0 \times 10^{-14}) = (1.6 \times 10^{-19})(4.6 \times 10^6)B

B = 0.0815 T

since the direction of force is along south so the magnetic field must be upwards

6 0
4 years ago
If I Throw a bowling ball and a tennis ball from a building, describe if one would hit the ground first and why.
olga nikolaevna [1]

Answer:

The bowling ball would

Explanation:

Because it contains more weight! And that will make it fall down quicker.

Hope it helped

3 0
3 years ago
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