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bija089 [108]
3 years ago
15

An object is fired from the ground at 200 meters per second at an angle of 30* with the horizontal

Physics
1 answer:
Soloha48 [4]3 years ago
7 0

Horizontal component = V cos(30°) = V (√3/2) = 73.2 m/s

Vertical component = V sin(30°) = V (0.5) = 100 m/s

In 6 seconds, the object travels horizontally (173.2 m/s x 6 sec) = 1,039 m

After 6 seconds, the object's height above the ground is

H = V₀t + 1/2 a t²

H = (100 m/s)(6 s) + (1/2) (-9.8 m/s²) (6 s)²

H = (600 m) - (4.9 m/s²) (36 s²)

H = (600 m) - (176.4 m)

Height = 423.6 m

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