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WITCHER [35]
4 years ago
6

Can Someone Help Me With This:​

Physics
1 answer:
qwelly [4]4 years ago
6 0
The first part is quite simple. Add up all of Selena’s earnings which equals- 186.

Then add up all of Drew’s earnings which is- 198.

Then put it in a ratio: 186:198, 186 to 198, 186/198.


I hope this is correct good luck.
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A 75.0-kg person is riding in a car moving at 20.0 m/s when the car runs into a bridge abutment. (a) calculate the average force
iragen [17]

(a) -1.5\cdot 10^6 N

First of all, we need to calculate the acceleration of the person, by using the following SUVAT equation:

v^2 -u ^2 = 2ad

where

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d = 1.00 cm = 0.01 m is the displacement of the person

Solving for a,

a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.01)}=-20000 m/s^2

And the average force on the person is given by

F=ma

with m = 75.0 kg being the mass of the person. Substituting,

F=(75)(-20000)=-1.5\cdot 10^6 N

where the negative sign means the force is opposite to the direction of motion of the person.

b) -1.0\cdot 10^5 N

In this case,

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d  = 15.00 cm = 0.15 m is the displacement of the person with the air bag

So the acceleration is

a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.15)}=-1333 m/s^2

So the average force on the person is

F=ma=(75)(-1333)=-1.0\cdot 10^5 N

7 0
4 years ago
15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
kolbaska11 [484]

Answer:

Explanation:

Given that,

Mass of first car

M1= 328kg

The car is moving in positive direction of x axis with velocity

U1 = 19.1m/s

Velocity of second car

U2 = 13m/s, in the same direction as the first car..

Mass of second car

M2 = 790kg

Velocity of second car after collision

V2 = 15.1 m/s

Velocity of first car after collision

V1 =?

This is an elastic collision,

And using the conservation of momentum principle

Momentum before collision is equal to momentum after collision

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

V1 = 14.04 m/s

The velocity of the first car after collision is 14.04 m/s

5 0
3 years ago
When acceptance and love are given to another only when certain expectations or standards are met, __________ is being demonstra
Anna71 [15]

Answer:

<u><em>conditional positive regard</em></u>

Explanation:

Condition Positive Regard can be described as a situation in which positivity, love or affection are only given when certain criteria or demands are met. Whereas on the contrary, an unconditional positive regard occurs when a person is loved without any demands or criteria.

Condition positive regards means to love or show affection for someone or something depending on its values in our eyes.

7 0
3 years ago
A sound wave has frequency of 430 Hz in air . Which of these is closet to the wavelength of this sound? ( The speed of sound in
Darya [45]
I think it would be E. The higher the object the less wavelength is possible.
5 0
3 years ago
Fill in the blank with the correct response.
viktelen [127]

Answer:

the answer is portfolio

Explanation:

7 0
3 years ago
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