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mars1129 [50]
4 years ago
7

Compare the planets Mars and Saturn. Describe how their common characteristics are similar and Compare the planets Earth and Nep

tune. Describe how are they different from each other
Physics
1 answer:
nordsb [41]4 years ago
4 0

Question no. 1. Compare the planets Mars and Saturn. Describe how their common characteristics are similar:

Answer:  Our solar system is located in the outer spiral arm of the milky way galaxy. our solar system has one sun and nine revolving planets and . namely  

  1. Mercury
  2. Venus
  3. Earth
  4. Mars
  5. Jupiter
  6. Saturn
  7. Uranus
  8. Neptune
  9. Pluto (small planet usually refer as dwarf)

Each star has its on moon/moons and has its own characteristics i.e , planet must be a celestial body , must have orbit around sun, have enough mass for self gravity, big enough to have gravity that clear its path from other same size object close to its orbit around sun.

Mars is the fourth from the sun and sixth is the Saturn from the sun in our solar system.

<u>Common in Characteristics of Mars and Saturn:</u>

  • Mars and Saturn both have celestial body.
  • Mars and Saturn both have enough mass for the gravity to get rid of rigid body forces.
  • Mars and Saturn both revolve around the sun in their own orbits.
  • Mars is the second smallest in the solar system while Saturn is second largest in the solar system.
  • Mars and Saturn both have their own moons. Mars has two while Saturn has 83 moons
  • Mars and Neptune both do not support life.    

Question no. 2. Compare the planets Earth and Neptune. Describe how are they different from each other

Answer:

Earth our home planet is the third from the sun and Neptune on the other hand is the eighth from the sun in the solar system.

<u>Common differences between Earth and Neptune</u>

  • Earth is the terrestrial planet while Neptune (Ice giant) is the Jovian planet.
  • Earth has no ring around it, Neptune has ring around it.
  • Earth is closer to the sun and Neptune is far distant from the sun.
  • Earth consists of rocks and metals on the other hand Neptune contain gases
  • Earth is smaller than the Neptune in the solar system.
  • Earth rotates slower and Neptune rotates faster.
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a force of 5.5 n is applied to an object. the moment arm for the force is 0.84 m. what is the torque produced by the force?
Kipish [7]

A force of 5.5N is applied to an object. The moment arm for the force is 0.84 m, the torque produced by the force is <u>4.62N-m</u>.

A force applied perpendicularly to a lever multiplied by its distance from the lever's fulcrum (the length of the lever arm) is its torque. We can find the torque from a force by taking the perpendicular component of that force and multiplying by the magnitude of the R vector where this R vector is the vector that points from the axis to the point where the force is applied.

To calculate torque produced by the force, we have-

Torque= forcexmoment arm

T = fxd

T =5.5Nx0.84m

T=4.62N-m.

To learn more about torque, visit---

brainly.com/question/20691242

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6 0
2 years ago
In which condition does a convex lens form an erect and enlarged image ? Give the application of this condition .​
asambeis [7]

Answer:

When the object is placed between F and O of a convex lens, the lens forms an erect and enlarged image.

Explanation:

7 0
3 years ago
A sample of nitrogen occupies 5.50 liters under a pressure of 900 torr at 25oC. At what temperature will it occupy 10.0 liters a
vitfil [10]

Answer:

<u>At 268.82°C</u> volume occupied by nitrogen is 10 liters at pressure of 900 torr.

Explanation:

Given:

Volume of a sample of nitrogen = 5.50 liters

Pressure = 900 torr

Temperature = 25°C

To find the temperature at which the nitrogen will occupy 10 liters volume at same pressure.

Solution:

Since the pressure is kept constant, so we can apply the temperature-volume law also called the Charles Law.

Charles Law states that the volume of a gas held at constant pressure is directly proportional to the temperature of the gas in Kelvin.

Thus, we have :

V ∝ T

\frac{V}{T}=k

where k is a constant.

For two samples of gases, the law can be given as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

From the data given:

V_1=5.5\ l

T_1=25\ \°C =(273+25)K= 298 K

V_2=10\ l

We need to find T_2.

Plugging in values in the formula.

\frac{5.5}{298}=\frac{10}{T_2}

Multiplying both sides by T_2.

T_2\times\frac{5.5}{298}=\frac{10}{T_2}\times T_2

\frac{5.5}{298}T_2={10}

Multiplying both sides by \frac{298}{5.5}

\frac{298}{5.5}\times\frac{5.5}{298}T_2=\frac{10\times 298}{5.5}

T_2=541.82\ K

T_2=541.82\ K-273\ K = 268.82\°C

Thus, at 268.82°C volume occupied by nitrogen is 10 liters at pressure of 900 torr.

7 0
3 years ago
A painter sits on a scaffold that is connected to a rope passing over a pulley. The other end of the rope rests in the hands of
Doss [256]

Solution :

a). From Newtons second law,

F = ma

The total tension force is 2T.

∴ 2T - (m + M)g = (m+ M)a

Then

$a=\frac{2T-(m+M)g}{m+M}$

$a=\frac{2\times 600-(52+63)9.8}{52+63}$

   $=0.63 \ m/s^2$

b). From the person,

   F = ma

 T - Mg + N = Ma

or N = Ma + Mg - T

        = (63 x 9.8) + (52 x 9.8) - 600

        = 617.4 + 509.6 - 600

        = 527 N

6 0
3 years ago
Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou
lyudmila [28]

Answer:

w = 1.976 rpm

Explanation:

For simulate the gravity we will use the centripetal aceleration a_c, so:

a_c = w^2r

where w is the angular aceleration and r the radius.

We know by the question that:

r = 60.5m

a_c = 2.6m/s2

So, Replacing the data, and solving for w, we get:

2.6m/s = w^2(60.5m)

W = 0.207 rad/s

Finally we change the angular velocity from rad/s to rpm as:

W = 0.207 rad/s = 0.207*60/(2\pi)= 1.976 rpm

5 0
3 years ago
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