A force of 5.5N is applied to an object. The moment arm for the force is 0.84 m, the torque produced by the force is <u>4.62N-m</u>.
A force applied perpendicularly to a lever multiplied by its distance from the lever's fulcrum (the length of the lever arm) is its torque. We can find the torque from a force by taking the perpendicular component of that force and multiplying by the magnitude of the R vector where this R vector is the vector that points from the axis to the point where the force is applied.
To calculate torque produced by the force, we have-
Torque= forcexmoment arm
T = fxd
T =5.5Nx0.84m
T=4.62N-m.
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Answer:
When the object is placed between F and O of a convex lens, the lens forms an erect and enlarged image.
Explanation:
Answer:
<u>At 268.82°C</u> volume occupied by nitrogen is 10 liters at pressure of 900 torr.
Explanation:
Given:
Volume of a sample of nitrogen = 5.50 liters
Pressure = 900 torr
Temperature = 25°C
To find the temperature at which the nitrogen will occupy 10 liters volume at same pressure.
Solution:
Since the pressure is kept constant, so we can apply the temperature-volume law also called the Charles Law.
Charles Law states that the volume of a gas held at constant pressure is directly proportional to the temperature of the gas in Kelvin.
Thus, we have :
∝ 

where
is a constant.
For two samples of gases, the law can be given as:

From the data given:



We need to find
.
Plugging in values in the formula.

Multiplying both sides by
.


Multiplying both sides by 



Thus, at 268.82°C volume occupied by nitrogen is 10 liters at pressure of 900 torr.
Solution :
a). From Newtons second law,
F = ma
The total tension force is 2T.
∴ 2T - (m + M)g = (m+ M)a
Then



b). From the person,
F = ma
T - Mg + N = Ma
or N = Ma + Mg - T
= (63 x 9.8) + (52 x 9.8) - 600
= 617.4 + 509.6 - 600
= 527 N
Answer:
w = 1.976 rpm
Explanation:
For simulate the gravity we will use the centripetal aceleration
, so:

where w is the angular aceleration and r the radius.
We know by the question that:
r = 60.5m
= 2.6m/s2
So, Replacing the data, and solving for w, we get:

W = 0.207 rad/s
Finally we change the angular velocity from rad/s to rpm as:
W = 0.207 rad/s = 0.207*60/(2
)= 1.976 rpm