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kap26 [50]
4 years ago
14

Three students work independently on a homework problem.

Mathematics
1 answer:
ololo11 [35]4 years ago
7 0

Answer:

a. 0.646

b. 0.0285

c. 0.0015

Step-by-step explanation:

Please refer to the tree diagram attached at the bottom of this answer.

a. Probability P of the three of them solving the problem:

P = P(A) · P(B) · P(C) = 0.95 · 0.85 · 0.80 = 0.646

b.  Only the first one:

P = P(A) · (1-P(B)) · (1- P(C)) = 0.95 · 0.15 · 0.20 = 0.0285

c. None of them:

P = (1-P(A)) · (1-P(B)) · (1- P(C)) = 0.05 · 0.15 · 0.20 = 0.0015

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The answer to this question would be 6
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Answer:

The second choice is the answer.

Step-by-step explanation:

In math, there are two types of numbers: real numbers and imaginary numbers. Imaginary numbers build upon the premise that the equation

x^2 +1 = 0 has no real solution. It is said that one of the imaginary solutions to this equation is <em>i</em>, or √-1. Real numbers are numbers that can represent the "distance" of a line. Real numbers have subsets known as natural numbers, whole numbers, integers, natural numbers. It also has a region of irrational numbers.

Natural numbers are numbers you use to count w/ your fingers (1, 2, 3 ...)

Whole numbers are natural numbers and 0 (0, 1, 2, 3 ...)

Integers are whole numbers and their opposites ( -1, 0, 1, ...)

Rational numbers integers and numbers that can be put into a fraction of two integers. for example, 1/2 is a fraction of the integers 1 and 2 ( -1, -1/2, 0, 1/2, 1 ...)

Irrational numbers are numbers that cannot be written as a simple fraction or cannot be written as terminating or repeating decimals (√2, π, <em>e, ...</em>).

The answer is not the first choice because it has whole numbers.

The answer is not the third choice because it has integers.

The answer is not the fourth choice because it has irrational numbers.

The answer is not the fifth choice because it has imaginary numbers.

The second choice is the one that has rational numbers and is the answer.

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10000 digits can be used for 4 digit A.T.M code.

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Given that A.T.M required 4 digit codes using the digits 0 to 9.  

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We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.

Now we have four places to be filled by 0 to 9 that is 10 numbers

Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .  

First digit can be selected in 10 ways that is from 0 to 9.

After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.

So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways

Hence 10000 digits can be used for 4 digit A.T.M code.

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