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Zielflug [23.3K]

2 years ago

14

I am literally in tears. Pls someone help me fast. This is a timed question. I will give all of my points to the answer if it is

right. Please!!!

1 answer:

Contact [7]2 years ago

4 0

<h2><em><u>hey dude ....</u></em></h2><h2 /><h2><em><u>hey dude ....14x +6 /3= -8 +4x</u></em></h2>

<h2><em><u>14x+6 = -24 +12x</u></em></h2>

<h2><em><u>2x+6= -24</u></em></h2>

<h2><em><u>2x= -30</u></em></h2>

<h2><em><u>x=15</u></em></h2><h2><em><u>x=15putting value of x in -3x^2 -7,</u></em></h2>

<h2><em><u>-3(15)^2 -7</u></em></h2>

<h2><em><u>-3(225)-7</u></em></h2>

<h2><em><u>-675 -7</u></em></h2>

<h2><em><u>-682</u></em></h2><h2 /><h2 />

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What is 4.110 in word form

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3 years ago

A reporter for a student newspaper is writing an article on the cost of off-campus housing. A sample was selected of 10 one-bedr

olga55 [171]

Answer:

(507.05, 592.95)

Step-by-step explanation:

Given data:

sample mean = $550, sample standard deviation S = $60.05

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For 95% confidence interval for the mean

mean ± M.E.

where M.E. is margin of error = $t_{n-1}, \alpha/2\times\frac{S}{\sqrt{n} }$

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6 0

2 years ago

You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building

nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

$h=\sqrt{x^2+y^2}$

The rate of change for the distance between you and the elevator is given by:

$\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}$

$-16=\frac{dh}{dy}*\frac{dy}{dt}$

$\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\$

Applying the chain rule:

$u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}$

Therefore, at x=300 and y = 500, dy/dt is:

$-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s$

The elevator is descending at 18.66 ft/s.

7 0

3 years ago