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Tomtit [17]
2 years ago
11

Simplify the expression -6y - 7y

Mathematics
2 answers:
Delicious77 [7]2 years ago
7 0

Answer:

-13y

Step-by-step explanation:

you just basically add and then u find that u exponent comes to be negative

vova2212 [387]2 years ago
7 0

Answer:

-13y

Step-by-step explanation:

Since this expression has the same coefficient, all you have to do is solve -6-7. Just follow the keep change change rule when subtracting negative numbers so -6 + -7 = -13. Therefore, your answer will be -13y.

Let me know if you do not understand or need more explanation.

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krok68 [10]
All but C can be used to gather resources.
5 0
3 years ago
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Write the equation of a line that is parallel to y=0.6x + 3 and that passes through the point (-3,-5)
Mkey [24]

Answer:

\large\boxed{y=0.6x-3.2}

Step-by-step explanation:

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

We have

y=0.6x+3

Parallel lines have the same slope. Therefore we have the equation:

y=0.6x+b

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

-5=0.6(-3)+b

-5=-1.8+b            <em>add 1.8 to both sides</em>

-3.2=b

Finally we have:

y=0.6x-3.2

8 0
3 years ago
PLS ANSWER ASAP THANKS TO YOU!
grandymaker [24]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

8 0
3 years ago
Is there anymore answers? I know it is obtuse but I don’t know if it is anymore.
Arisa [49]

Answer:

Hope this helps

Step-by-step explanation:

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3 years ago
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