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drek231 [11]
3 years ago
8

autopilot aviation sells model airplanes for $125. Dale loves to build model airplanes, and knows the store is offering a sell t

oday. When he gets to the store, there are no sale signs. However, his model airplane rings up for $97.75. What percent off the original price did Dale receive?​
Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

Step-by-step explanation:

125x = 97.75

x = 0.782

1 - 0.782 = 0.218

21.8% off the original price

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Simplify 3.7x+(0.5-6y)+0.8-(1.7x+1-2.3y)
hammer [34]

Answer:

2x-3.7y+0.3

Simplify the expression.

Step-by-step explanation:

6 0
3 years ago
Which two numbers doesStartRoot 61 EndRoot lie between on a number line?
denpristay [2]

Answer:

Between 7 and 8

Step-by-step explanation:

6^2 = 36

7^2 = 49

8^2 = 64

9^2 = 81

since 61 is between 7^2 and 8^2, √61 is between 7 and 8

7 0
3 years ago
Read 2 more answers
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

5 0
3 years ago
Y+5<br> ——=0 solve for y<br> X-1
Ira Lisetskai [31]

Answer:

y = -5

Step-by-step explanation:

see the pic for the steps . .

5 0
3 years ago
Can someone help me.​
salantis [7]

Answer:

see explanation

Step-by-step explanation:

substitute the values of x in the table into g(x)

Using the rule of exponents

a^{-m} = \frac{1}{a^{m} }

g(- 2) = 4^{-2} = \frac{1}{4^{2} } = \frac{1}{16}

g(- 1) = 4^{-1} = \frac{1}{4}

g(0) = 4^{0} = 1

g(1) = 4^{1} = 4

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8 0
3 years ago
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