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2 years ago

The perimeter of the rectangle below is 84 units. Find the length of side VW.

Mathematics

1 answer:

Anestetic [448]2 years ago

8 0

Answer:

18.

Step-by-step explanation:

1) formula of the perimeter given in the condition is:

p=2(VW+XV) or p=2(VY+XY).

Note, VW=XY and XV=VY;

2) if to substitute p=84, VW=2z+2 and XV=3z into the formula above, then

2(2z+2+3z)=84, ⇔ 5z+2=42; ⇒ z=8.

3) if z=8, then VW=2z+2=2*8+2=18.

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Definitions of ASA SAS AAS, can someone dumb it down plz?

Veseljchak [2.6K]

Answer:

Hope this helps.

Step-by-step explanation:

So for ASA, the two triangles have to have two angles congruent, and in the middle of those angles, they have to have a line that's congruent.

For SAS, the two triangles have to have two lines congruent, and in the middle of those lines, they have to have an angle that's congruent.

For AAS, the two triangles have to have two angles congruent, but the line that's congruent has to be on the side, not in the middle.

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3 years ago

The amount of money that college students spend on rent each month is usually between $300 and $600. However, there are a few st

velikii [3]

The correct answer would be b. range. you take the largest amount and subtract the smallest amount giving you the range.

6 0

3 years ago

What is 5.300 equivalent to

S_A_V [24]

It is equivalent too 5.3 and 5.30

7 0

3 years ago

the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence

Crazy boy [7]

Answer:

The sequence is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ( $S_{5}$ ) = 250

or, $\frac{n}{2} [{2a+(n-1)d}] = 250$

or, $\frac{5}{2} [2*10 + 4d]=250$

or, $\frac{5}{2} * 4[5+d]=250$

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

8 0

3 years ago

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.