Step-by-step explanation:
f°g=![f(g(x))](https://tex.z-dn.net/?f=f%28g%28x%29%29)
![g(x)=x^2-6x](https://tex.z-dn.net/?f=g%28x%29%3Dx%5E2-6x)
![f(x)=1/x](https://tex.z-dn.net/?f=f%28x%29%3D1%2Fx)
![f(g(x))=](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D)
![\frac{1}{x^2-6x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%5E2-6x%7D)
if the denominator is zero the number is undefined which makes it not in the domain of the function
set
equal to 0
the values for x is 0 or 6
so the only value that is not in the domain of f°g is 0 and 6
Hope that helps :)
It’s a diagram ur welcome
Answer: PEMDAS
Step-by-step explanation: You wanna add 1 to both sides and get 3√x = 1. Then you wanna multiply 3 by 3√x which leaves you with x cause it canceled out. But remember to multiply 3 on both sides so x = 1 sq rt 3. Which is just 1.
x = 1
Given:
Let P= profit
let n= no. of tacos sold per day
Sol'n:
P= 3.25n-210
the profit needs to be positive, thus
3.25n>210
n>210/3.25
n> 64.615
they can only sell whole tacos, therefore they must sell at least 65 tacos to make a profit and that profit is:
P=3.25n-210
P=3.25*65 - 210
P= 211.25 -210
P= 1.25
$1.25 profit