The sampling method used to examine a population when the auditor wants to estimate a continuous amount (or value) of the popula
1 answer:
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Answer:
Option (c)
Chuy will save more than he needs and will meet his goal in less than 27 week.
Step-by-step explanation:
Given that, Chuy wants to buy a new television. The television cost is $1,350.
He decides to save the same amount of money each week.
After 8 weeks he saved $440.
Each week he saved
=$ 55
If he saved $55 each week.
At the end of 27 week he will save = $(27×55)
=$1485
Therefore he will save $1485 at the end of 27th week.
The saved money is more than the cost price of the television.
Therefore Chuy will meet his goal in less than 27 weeks.
Answer:
Correct option:
We are 95% certain that the confidence interval of 18.6 to 21.3 includes the true average number of chocolate chips per cookie.
Step-by-step explanation:
The general formula for the (1 - <em>α</em>)% confidence interval for population<em> </em>mean is:
Here:
= sample mean
CV = critical value
= standard error of mean.
The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.
Or, the (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.
The 95% confidence interval for the mean number of chocolate chips per cookie is (18.6, 21.3).
This 95% confidence interval implies that there is a 0.95 probability that the true mean number of chocolate chips per cookie is between 18.6 and 21.3.
Thus, the correct option is:
"We are 95% certain that the confidence interval of 18.6 to 21.3 includes the true average number of chocolate chips per cookie. "