Answer:
The speed rate of the plane in still air is 1006.67 km/h
The speed rate of the wind is 246.67 km/h
Step-by-step explanation:
To answer the question, we let the speed of the plane in still air = x km/h
Let the speed of the wind = y km/h
Therefore,
4560/(x - y) = 6 hours and
3720/(x + y) = 3 hours
4560 = 6·x - 6·y.........(1)
3720 = 3·x + 3·y ........(2)
Multiplying equation (2) by 2 and add to (1) gives
12080 = 12·x
x = 12080/12 = 
km/h
Substituting the value of x in (1) gives
4560 = 6040 - 6·y
6·y = 1480
y = 1480/6 = 
The speed rate of the plane in still air = 1006.67 km/h
The speed rate of the wind = 246.67 km/h.
should be 916191, because 916191 over 1 would be 916191
The equation would look like this: 14+x= 17. To find the answer, you can either subract 17-14 or add to fourteen until you get to seventeen. Your answer is 3. It's the same either way. Hope this helps.
The Pyth. Thm. applies here:
(√x + 1)^2 + (2√x)^2 = (2√x + 1 )^2
Expanding the squares:
x + 2sqrt(x) + 1 + 4x = 4x + 4sqrt(x) + 1
Let's subtract x + 2sqrt(x) + 1 + 4x from both sides:
4x + 4sqrt(x) + 1
-(x + 2sqrt(x) + 1 + 4x)
-------------------------------
3x + 2sqrt(x) - 4x = 0
Then 2sqrt(x) = x
Squaring both sides, 4x = x^2, or x^2 - 4x = 0. Then (x-4)x = 0, and the two possible solutions are 0 and 4.
Check these results by substitution. Does the Pyth. Thm. hold true for x=4?
So first we write out their respective charges
A=65+30x (x=hours of A)
B=30+47.5y (x= hours of B)
we want to know when A and B are equal so just set them to be equal
65+30x=30+47.5x
subtract 30 from both sides
35+30x=47.5x
multiplyboth sides by 2 to get rid of the nasty decimal
70+60x=95x
subtract 60x from both sides
70=35x
divide both sides by 35
2=x
they must work 2 hours for them to be equal
