Inverse variation is of the form:
y=k/x, which we can express as:
yx=k we are given the point (2/3, 7) so we can solve for k
7(2/3)=k
14/3=k
y=14/(3x), so when x=7/3
y=(14/3)/(7/3)
y=(14/3)(3/7)
y=2
D) i think
, all values of x that are greater than equal to 1
7
8
It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
Answer:
Im pretty sure it's false because 7.4p could 74, 148, 222 or 296. so it would be the other way around. It's false.
Step-by-step explanation: