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2 years ago

Find the distance between the points (7, -2) and (2, -10).

Mathematics

1 answer:

katrin2010 [14]2 years ago

3 0

Answer:

$\sqrt{89}$

Step-by-step explanation:

d = $\sqrt{(x_{1}-x_{2} )^{2} +(y_{1} -y_{2} )^{2} }$

d = $\sqrt{(7-2)^{2} +(-2+10)^{2} }$

d = $\sqrt{5^{2} +(-8)^{2} }$

d = $\sqrt{25+64}$

d = $\sqrt{89}$

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White raven [17]

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4 years ago

Read 2 more answers

Find the area of a circle with a circumference of 6.28 unitesz

Anni [7]

Answer:

3.14 square units

Step-by-step explanation:

Circumference of a circle = 2πr

2πr = 6.28

r = 6.28/2π

r = 3.142/π

Area of a circle = πr^2

slot in the value of r

Area of the circle = π( 3.142/π)^2

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3 years ago

a private club was reduced by five members each week for 45 weeks what was the total change in the club size

Arturiano [62]

The club was reduced by 225 people in all.

5 0

4 years ago

Use the distance formula to find the perimeter of the triangle below. Round you answer to the nearest hundredth.

Murrr4er [49]

jAlright, let's take this problem step-by-step:

What is the perimeter:

⇒ all the side-lengths added up

⇒ need to find side-length using distance formula

$Distance_._. Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

- (x₁,y₁): first point

- (x₂,y₂): second point

Let's solve:

Find length of AC

⇒ first point: (5,7)

⇒ second point: (3,3)

$Distance =\sqrt{(3-5)^2+(3-7)^2} =\sqrt{4+16} =\sqrt{20} =4.472$

Find length of AB

⇒ first point: (5,7)

⇒ second point:(8,6)

$Distance=\sqrt{(8-5)^2+(6-7)^2} =\sqrt{9+1} =\sqrt{10}=3.162$

Find length of BC

⇒ first point: (8,6)

⇒ second point: (3,3)

$Distance = \sqrt{(3-8)^2+(3-6)^2} =\sqrt{25+9} =\sqrt{34}=5.831$

Now let's solve for the perimeter:

$Perimeter = 4.472+ 3.126+ 5.831=13.429$

Answer: 13.43 (rounded to the nearest hundredth)

Hope that helps!

#LearnwithBrainly

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2 years ago

In circle R with m angle QRS= 90 and QR= 3 units find the length of arc QS round to the nearest hundredth

Advocard [28]

Answer:

4.71 units

Step-by-step explanation:

The formula for arc length =

2πr × θ/360

From the above question,

r = QR = 3 units

θ = angle QRS= 90 = 90°

The length of the arc is calculated as:

2 × π × 3 × 90/360

= 4.7123889804 units

Approximately to the nearest hundredth = 4.71 units

8 0

3 years ago