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iragen [17]
3 years ago
10

a rectangular prism has a volume of 1374.28 cubic inches.The prism is 9.4 inches wide and 17.2 inches long.What is the height of

the prism?
Mathematics
1 answer:
NISA [10]3 years ago
6 0
The volume V of a prism can be found by:
The volume of a rectangular prism can be found through:
V=lwh
Where l is the length, w is the width, and h is the height.

The height can be found by rearranging the equation to:
h= \frac{V}{wl}

Take the volume (1374.28) and divide it by the length times the width (9.4*17.2=161.68).
1374.28/161.68= 8.5 inches is the height of the prism.
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A blackjack player at a Las Vegas casino learned that the house will provide a free room if play is for four hours at an average
marysya [2.9K]

Answer:

a) player’s expected payoff is $ 240

b) probability the player loses $1000 or more is 0.1788

c)  probability the player wins is 0.3557

d) probability of going broke is 0.0594

Step-by-step explanation:

Given:

Since there are 60 hands per hour and the player plays for four hours then the sample size is:

n = 60 * 4 = 240

The player’s strategy provides a probability of .49 of winning on any one hand so the probability of success is:

p = 0.49

a)

Solution:

Expected payoff is basically the expected mean

Since the bet is $50 so $50 is gained when the player wins a hand and $50 is lost when the player loses a hand. So

Expected loss =  μ

                        = ∑ x P(x)

                        = 50 * P(win) - 50 * P(lose)

                        = 50 * P(win) + (-50) * (1 - P(win))

                         = 50 * 0.49 - 50 * (1 - 0.49)

                        = 24.5 - 50 ( 0.51 )

                        = 24.5 - 25.5

                        = -1

Since n=240 and expected loss is $1 per hand then the expected loss in four hours is:

240 * 1 = $ 240

b)

Using normal approximation of binomial distribution:

n = 240

p = 0.49

q = 1 - p = 1 - 0.49 = 0.51

np = 240 * 0.49 = 117.6

nq = 240 * 0.51 = 122.5

both np and nq are greater than 5 so the binomial distribution can be approximated by normal distribution

Compute z-score:

z = x - np / √(np(1-p))

  = 110.5 - 117.6 / √117.6(1-0.49)

  = −7.1/√117.6(0.51)

  = −7.1/√59.976

  = −7.1/7.744417

  =−0.916789

Here the player loses 1000 or more when he loses at least 130 of 240 hands so the wins is 240-130 = 110

Using normal probability table:

P(X≤110) = P(X<110.5)

             = P(Z<-0.916)

             = 0.1788

c)

Using normal approximation of binomial distribution:

n = 240

p = 0.49

q = 1 - p = 1 - 0.49 = 0.51

np = 240 * 0.49 = 117.6

nq = 240 * 0.51 = 122.5

both np and nq are greater than 5 so the binomial distribution can be approximated by normal distribution

Compute z-score:

z = x - np / √(np(1-p))

  = 120.5 - 117.6 / √117.6(1-0.49)

  = 2.9/√117.6(0.51)

  = 2.9/√59.976

  = 2.9/7.744417

  =0.374463

Here the player wins when he wins at least 120 of 240 hands

Using normal probability table:

P(X>120) = P(X>120.5)

              = P(Z>0.3744)  

             =  1 - P(Z<0.3744)

             = 1 - 0.6443

             = 0.3557

d)

Player goes broke when he loses $1500

Using normal approximation of binomial distribution:

n = 240

p = 0.49

q = 1 - p = 1 - 0.49 = 0.51

np = 240 * 0.49 = 117.6

nq = 240 * 0.51 = 122.5

both np and nq are greater than 5 so the binomial distribution can be approximated by normal distribution

Compute z-score:

z = x - np / √(np(1-p))

  = 105.5 - 117.6 / √117.6(1-0.49)

  = -12.1/√117.6(0.51)

  = -12.1/√59.976

  = -12.1/7.744417

  =−1.562416

Here the player loses 1500 or more when he loses at least 135 of 240 hands so the wins is 240-135 = 105

Using normal probability table:

P(X≤105) = P(X<105.5)

             = P(Z<-1.562)

             = 0.0594

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Answer:

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4 0
2 years ago
Which term describes the set of all possible output values for a function?
dexar [7]
The set of all output values for a function is called the range.
3 0
3 years ago
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Find the obtuse angle between the following pair of straight lines.
ioda

Given:

y=-2

y=\sqrt{3}x-1

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

y=mx+b     ...(i)

where, m is slope and b is y-intercept.

The given equations are

y=0x-2

y=\sqrt{3}x-1

On comparing these equations with (i), we get

m_1=0

m_2=\sqrt{3}

Angle between two lines whose slopes are m_1\text{ and }m_2 is

\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|

Putting m_1=0 and m_2=\sqrt{3}, we get

\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|

\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|

\tan \theta=\pm \sqrt{3}

Now,

\tan \theta= \sqrt{3} and \tan \theta=-\sqrt{3}

\tan \theta= \tan 60^\circ and \tan \theta=\tan (180^\circ-60^\circ)

\theta= 60^\circ and \theta=120^\circ

120>90, so it is an obtuse angle and 60, so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

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Find ten rational number between –3and–2​
creativ13 [48]

Answer:0

Step-by-step explanation:

Find the middle of the 2 numbers

6 0
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