Answer: There is a probability of 0.05 that there is neither truck is available.
Step-by-step explanation:
Since we have given that
Probability that the first truck is available = 0.75
Probability that the second truck is available = 0.50
Probability that both trucks are available = 0.30
So, probability that either first truck or second truck is available is given by
We need to find the probability that neither truck is available.
so, P(A∪B)'=1-P(A∪B)
Hence, there is a probability of 0.05 that there is neither truck is available.
Probability ( a flowering plant or fruit plant) is 
and Probability (neem plant or peepal plant) is 
.
Step-by-step explanation:
Given,
Number of neem plant = 125
Number of peepal plant = 165
Number of creppers plant = 50
Number of fruit plant = 150
Number of flowering plant = 110
To find the probability ( a flowering plant or fruit plant)
and probability ( neem or peepal)
Formula
P( A or B) = P(A) + P(B)
Probability ( a flowering plant or fruit plant) = 
= 
=
And,
Probability (neem plant or peepal plant) = 
= 
=
<u>Answer:</u>
9. x = 12
10. x = 31
<u>Step-by-step explanation:</u>
9. Corresponding angles are equal, so technically you can move that (7x - 20) to be diagonal with the (4x + 16). Along with the corresponding angle, diagonal angles are equal to each other. Therefore you can set (7x - 20) equal to (4x + 16) to find x.
7x - 20 = 4x + 16
Solve
3x - 20 = 16
3x = 36
x = 12
Therefore x is equal to 12
<u>Check:</u>
4(12) + 16
= 64
7(12) - 20
= 64
10. All angles in a triangle have to add up to 180 degrees. Therefore, you can write your equation like this:
x + 2x + 25 + 2x = 180
Combine like terms
5x + 25 = 180
Solve
5x = 155
x = 31
Therefore, x = 31.
<u>Check:</u>
31 + 2(31) + 25 + 2(31) = 180
31 + 62 + 25 + 62 = 180
180 = 180
<em>I hope this helps!!</em>
<em>- Kay :)</em>
<em />
Answer:
- arc BF = 76°
- ∠M = 31°
- ∠BGE = 121°
- ∠MFB = 111°
Step-by-step explanation:
(a) ∠FBM is the complement of ∠FBC, so is ...
∠FBM = 90° -52° = 38°
The measure of arc BF is twice this angle, so is ...
arc BF = 2∠FBM = 2(38°)
arc BF = 76°
__
(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...
∠M = (1/2)(138° -76°) = 62°/2
∠M = 31°
__
(c) arc FC is the supplement to arc BF, so has measure ...
arc FC = 180° -arc BF = 180° -76° = 104°
∠BGE is half the sum of arcs BE and FC, so is ...
∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2
∠BGE = 121°
__
(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...
∠MFB = 180° -∠M -∠FBM = 180° -31° -38°
∠MFB = 111°
