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saw5 [17]
2 years ago
12

The ratio between the modulating signal voltage and the carrier voltage is called?.

Engineering
1 answer:
Talja [164]2 years ago
7 0

The ratio between the modulating signal voltage and the carrier voltage is called modulation index.

<h3>What is a sideband?</h3>

A sideband can be defined as a band of frequencies that are lower or higher than the carrier frequency due to the modulation process. This ultimately implies that, a sideband will either be lower than or higher than the carrier frequency.

<h3>What is a modulation index?</h3>

A modulation index can be defined as the ratio of the modulating signal voltage to the carrier voltage.

In this context, we can reasonably infer and logically deduce that the ratio which exist between the modulating signal voltage and the carrier voltage is generally referred to as a modulation index.

Read more on modulation index here: brainly.com/question/13265507

#SPJ1

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A polymeric extruder is turned on and immediately begins producing a product at a rate of 10 kg/min. An operator realizes 20 min
hodyreva [135]

Answer:

The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.

The production rate function M(t) is:

m(t)=[H(t)\cdot10+H(t-20)\cdot5-H(t-80)\cdot14+H(t-81)\cdot9]kg/min (1)

The Laplace transform of this function is:

\displaystyle m(s)=[\frac{10+5e^{-20s}-14e^{-80s}+9e^{-81s}}{s}]kg/min    (2)

Explanation:

The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.

For the Laplace transform we use the following rules:

\mathcal{L}[f(x)+g(x)]=\mathcal{L}[f(x)]+\mathcal{L}[g(x)]=F(s)+G(s)    (3)

\mathcal{L}[aH(x-b)]=\displaystyle\frac{ae^{-bs}}{s}    (4)

4 0
4 years ago
Eagletrons are all-electric automobiles produced by Mogul Motors, Inc. One of the concerns of Mogul Motors is that the Eagletron
Ronch [10]

Answer:

Mogul executives takes samples of n=8 eagletrons at a time.

They found that the average is 3.25 mph.

For n = 8,

D4 =1.864(table value)

D3=0.136(table value)

The upper and lower control limits are found as

UCL =1.864 ×3.25= 6.058

LCL = 0.136 ×3.25= 0.442

3 0
3 years ago
Think for a moment about the potential problems with big data that the speaker mentioned:
Natalka [10]

Answer: 1. sadly yes, some people are treated unfairly for crimes people yet have commited. 2. no 3. yes

Explanation:

i did this last year

5 0
3 years ago
Read 2 more answers
What is the importance of knowing the parts and function of the ignition system in servicing your own vehicle
lisov135 [29]

Answer:

El conocer la función del sistema nervioso permite comprender la estructura del cuerpo. Puesto que, toda acción que se se realice en ella dependerá del sistema nervioso para que sea eficaz

4 0
2 years ago
Some aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 35 MPa m . It has bee
GaryK [48]

Answer:  Fracture will not occur since Kc (32.2 MPa√m) ∠ KIc (35  MPa√m).

Explanation:

in this question we are asked to determine if an aircraft will fracture for a given fracture toughness.

let us begin,

from the question we have that;

stress = 325 MPa

fracture toughness (KIc) = 35  MPa√m

the max internal crack length = 1.0 m

using the formula;

Y = KIc/σ√(πα)    ---------------(1)

solving for Y we have;

Y =  35 (MPa√m) / 250 (MPa) √(π × 2×10⁻3/2m)

Y = 2.50

so to calculate the fracture roughness;

Kc = Y × σ√(πα)   = 2.5 × 3.25√(π × 1×10⁻³/2) = 32.2 MPa√m

Kc = 32.2 MPa√m

From our results we can say that fracture will not occur since Kc (32.2 MPa√m) is less than KIc (35  MPa√m) of the material.

cheers i hope this helps!!!!

8 0
3 years ago
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