Heather is troubleshooting a computer at her worksite. She has interviewed the computer’s user and is currently trying to reprod
1 answer:
You might be interested in
Answer:
Part A:
Part B:
(Psi)
Explanation:
Part A:
Line Pressure is 1500 KPa
We need a conversion factor which converts KPa to lb/ft^2.
In order to convert 1500 KPa to lb/ft^2, we proceed as:
1500 KPa is 31328.145 lb/ft^2
Part B:
We will use the same procedure we did in Part A:
1 ft= 12 in
Converting
(Psi)
1500 KPa is 217.55656 lb/in^2 (psi)
Answer:
Explanation:
Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz
Zero at -200MHz, zero at infinity.
A) A(s) = 100FH(s)
B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz
(2): 2pi × 20 × 10^6= 4pi × 10^6 MHz
Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.
T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)
