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3 years ago

2. When manipulating your pedals, you should use your

Engineering

2 answers:

astra-53 [7]3 years ago

7 0

Answer:

D. left foot for the accelerator and your right foot for the brake.

* Hopefully this helps:) mark me the brainliest:)!!

dolphi86 [110]3 years ago

6 0

Answer:

The Correct Answer is B

Explanation:

During stimulating the right pad is applied on pushing the pedal and while applying to brake the right pad is applied on the braking lever.
The left foot is located on the base station granted in the footwell of the operator section.
The left foot can be applied to the coupling pedal when shifting gears in a hand-operated vehicle.

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Technicians have to determine the flow rate of water in a pipe with the aid of a venturi installation and a mercury au.oaeter. T

Schach [20]

Answer:

Manometric difference x=142.85 mm.

Explanation:

Given :

Pipe diameter $d_1=40 mm$

venturi meter $d_2=20 mm$

We can know that discharge through venturi meter is given as

$Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt {A_1^2-A_2^2}}$

$A_1=1.24\times 10^{-3},A_2=3.12\times 10^{-4}$

$Q=A_1V_1$

$Q=1.24\times 10^{-3}\times 1.5=0.00186 m^3/s$

$0.00186=0.97\dfrac{1.24\times 10^{-3}\times 3.12\times 10^{-4} \sqrt{2gh}}{\sqrt {(1.24\times 10^{-3})^2-(3.12\times 10^{-4})^2}}$

h=1.8 m

We know that $h=x\left (\dfrac{\rho_{hg}}{\rho_w}-1\right )$

Where x is the manometric deflection

⇒ $1.8=x\left (\dfrac{13600}{1000}-1\right )$

So x=14.28 mm

Manometric difference x=142.85 mm.

7 0

3 years ago

A square isothermal chip is of width w = 5 mm on a side and is mounted in a substrate such that its side and back surfaces are w

nirvana33 [79]

Answer:

Q(h=200)=0.35W

Q(h=3000)=5.25W

Explanation:

first part h=200W/Km^2

we must use the convection heat transfer equation for the chip

Q=hA(Ts-T∞)

h= convective coefficient=200W/m2 K

A=Base*Leght=5mmx5mm=25mm^2

Ts=temperature of the chip=85C

T∞=temperature of coolant=15C

Q=200x2.5x10^-5(85-15)=0.35W

Second part h=3000W/Km^2

Q=3000x2.5x10^-5(85-15)=5.25W

5 0

3 years ago

What should i do to my nissan 350z, twin charge it or have twin turbos, to twin turbos with a super charger? i want it to be ove

bulgar [2K]

Answer:

Explanation:

It just makes sense

4 0

3 years ago

Simplify the following expressions, then implement them using digital logic gates. (a) f = A + AB + AC (b) f = AB + AC + BC (c)

Tema [17]

<u>Explanation</u>:

(a)

$f=A+A B+A C\\=A[1+B+C]=A \quad[1+x=1]\\F=A$

No gate is required to implement this function

(b)

$\begin{aligned}&\ f=A B+\bar{A} C+B C\\&\therefore f=A B+A C\end{aligned}$ $\begin{array}{l}(A B+\bar{A} C+B E=A B+\bar{A} C \\B C \text { is redendant })\end{array}$

Note: Refer the first image.

(c)

$\begin{aligned}f &=\overline{A+B}+A \bar{B}+B \bar{C} \\&=(\bar{A} \bar{B})+A \bar{B}+B \bar{C} \\&=\bar{B}[A+\bar{A}]+B \bar{C} \\& F=\bar{B}+B \bar{C} =\bar{B}+\bar{C}\end{aligned}$

Note: Refer the second image

(d)

$\begin{aligned}f=& A B \bar{c}+\overline{A+\bar{c}} \\=& A B \bar{c}+\bar{A} \bar{c}=\bar{A} B \bar{c}+\bar{A} c \\f=& \bar{A}[c+B \bar{c}] . \\& f=\bar{A} B+\bar{A} c=\bar{A}(B+c)\end{aligned}$

Note: Refer the third image

(e)

$\begin{aligned}f=& A \bar{B}+\bar{B} C+A \bar{B} \\&=\bar{B}[A+\bar{A}+c] \\&=\bar{B}[1+C]\end{aligned}$

$f=\frac{}{B}$

(f)

$\begin{aligned}f &=A B C+A B D+A B C \\&=A B[C+C]+A B D \\&=A B+A B D \\&=B[A+A D] \\&=B[A+D] \\\therefore & A=B[A+D]\end{aligned}$

Note: Refer the fourth image

6 0

3 years ago

At audio frequencies (below 20kHz), electromagnetic waves have very ____ wavelengths. The wavelength is typically much larger th

netineya [11]

Answer:

broad, transmission or power lines, electrical circuit theory

Explanation:

Electromagnetic waves have quite broad wavelengths for audio frequencies. Normally, the wavelength is larger than any of wires used in circuit. Long transmission or power line might be an exception. If the wavelength is much smaller than length of a wire, the basic principles of electronic circuits apply and the principle of electrical circuits is not needed

For wavelength much smaller than length of wire given, the given elements behave as distributed element, so for this condition Maxwell equation is apply

4 0

3 years ago