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1 year ago

6

Which of the following statements concerning the linear correlation coefficient are true?

2 answers:

Dmitry [639]1 year ago

4 0

Answer:

I and IV... ig (:

Butoxors [25]1 year ago

3 0

I and IV because i’m very extremely intelligent

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The domain of the following relation: R {(6, -2), (1, 2), (-3, -4), (-3, 2)} is

monitta

The domain is the set of possible inputs, i.e. the x-coordinates of the points.

Here those are 6, 1 and - 3 which in order is -3, 1, 6.

Then the answer is {-3, 1, 6}.

By the way note that this relation is not a function. Do you know why?

Because the image of -3 is not stated unambiguosly.

5 0

2 years ago

Kendra is buying gifts for 5 friends.

Blizzard [7]

Answer:

She could spend $18 on each for the 4 friends

Step-by-step explanation:

100-28= 72

72/4=18

4 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago

Simplify 5/6<br><br> IM KINDA CONFUSED UMM PLEASE HELP

gulaghasi [49]

The answer is 5/6. It can’t be simplified any further.

4 0

3 years ago

Read 2 more answers

20 points!!! first answer gets brainliast. Don't need too much explanation thank you!

KengaRu [80]

Answer:

The answer to your question is below

Step-by-step explanation:

2. $\sqrt{-128}$ Just find the prime factors of 128 and simplify

$\sqrt{-2^{7}} = \sqrt{-2^{6} 2} = 2^{3}i \sqrt{2}$

$8i\sqrt{2}$

3.- $\sqrt{-9} + \sqrt{-16}$ Get the square roots and simplify

3i + 4i

7i

4.- None of the choices is equal to one, because the exponents are pair.

5.- 1/3x² + 10 = 7

1/3x² = 7 - 10

1/3x² = -3

x² = -3(3)

x² = -9

x = ±3i

8 0

3 years ago