Answer:
1.0988889e+13
Step-by-step explanation:
and i oop
The friction force exerted on the 2400kg car is 9408 Newtons
<h3>
What force will be exerted on the 2400kg car?</h3>
First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:
F = k*M
Where F is the force, M is the mass and k is the constant of proportionality.
We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:
6272N = k*1600kg
Solving for k we get:
k = (6272N)/(1600 kg) = 3.92 N/kg
Then the proportional relationship is:
F = (3.92 N/kg)*M
So if M = 2400kg, we have:
F = (3.92 N/kg)*2400kg = 9408 N
So the friction force exerted on the 2400kg car is 9408 Newtons
If you want to learn more about proportional realtions:
brainly.com/question/12242745
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4-1=3 plus I don’t like it so when he asks u that say no
Answer:
The hypothesis should be retained
Step-by-step explanation:
We are given:
N= 16
n = 4


Level of significance, a = 0.05
From the given data, our ANOVA table will be:




Note: proper ANOVA table is attached
The statistic will be written as:

T = 8/4 = 2
Therefore


The hypothesis should be retained, because we no know that the statistic is in the acceptance area.
Answer:
3log2+log3+logx
Step-by-step explanation:
log8(3x) can be written as log(8•3x)
Log laws says that log(ab)=log(a)+log(b)
So log (8•3•x)=log8+log3+logx
log8 can be written into prime factorization of log(2^3) and by more log laws that can be written as 3log2