Answer:
The answer is D because you should starts at -2 on the y-axis and moves up 3 and right 1.
I believe the first quartile would be 24 and the third would be 8. Sorry if this wasn't correct. I haven't done this in a while.
Hope it helps
So the equation of the red graph is already given to us:
. I assume you meant the blue graph?
We can use the vertex form:
, where
is the vertex. (We can ignore
because
is 1 for this graph.) Remember that the vertex is the maximum or minimum of a parabola and the point that the line of symmetry passes through. For f(x) the vertex is (0,0).
The vertex for
is at
on the coordinate plane. (4 left, 2 down)
Plug into the vertex form:

The double negative becomes a positive, and then you're done:

Answer:
- maximum height: 498 ft
- distance from point of release: 70 ft
Step-by-step explanation:
A graphing calculator can show the answers to these questions.
___
For quadratic ax²+bx+c, the x-value of the vertex is ...
x = -b/(2a)
For the given expression, the vertex is ...
x = -14/(2(-0.1)) = 70
The distance from the point of release to the point of maximum height is 70 feet.
__
The height of the ball at that point is ...
f(70) = (-0.1·70 +14)70 +8 = 7·70 +8 = 498 . . . . feet
The maximum height is 498 feet.
To solve, first add 25 to both sides to get

Then factor to get



There is only one solution, x = 5.