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DiKsa [7]
3 years ago
12

Can some one help me I’ll mark brainliest answer‼️‼️

Mathematics
1 answer:
gogolik [260]3 years ago
4 0

Answer:

i think its 5.652 hope it helps

Step-by-step explanation:

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A formula for a function y=f(x) is f(x)=x^2-10x,xless than or equal 5. Find f^-1(x) and indentify the domain and range of f^-1(x
evablogger [386]
F(x) =x² - 10x,  f⁻¹(x) =?

1st find the missing square of x²-10x, ==> (x-5)² - 25

y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5

Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}

6 0
3 years ago
Bart's drive to the airport takes 232323 minutes. What is the latest time Bart can leave to arrive at the airport by a quarter b
Nikitich [7]
It take 23 mins for the drive

He needs to reach the airport by a quarter before 6

a quarter before 6 = 5.45
So he needs to leave 23 mins before 5.45

23 mins before 5.45 = 5.22
6 0
3 years ago
Plz help I want to ace this
nikklg [1K]

Answer:

B

Step-by-step explanation:

You multiply the 3 numbers.

6 0
2 years ago
What is 8.7 + w = 5.1
Vanyuwa [196]
8.7+w=5.1
W=-3.6
Have a great day and stay in school
5 0
3 years ago
Read 2 more answers
JK is formed by J(-12,3) and K(8,-5). If line r is the perpendicular bisector of JK, write an equation for r in slope-intercept
dem82 [27]

Answer:

  • y = 5/2x + 4

Step-by-step explanation:

<u>Midpoint of JK:</u>

  • x = (-12 + 8)/2 = -4/2 = -2
  • y = (3 - 5)/2 = -2/2 = -1

<u>Slope of the line JK:</u>

  • m = (-5 - 3)/(8 - (-12)) = -8/20 = -2/5

Perpendicular lines have negative reciprocal slopes.

So the line r has a slope 5/2 and passes through the point (-2, -1)

<u>Equation of r:</u>

  • y = 5/2x + b
  • -1 = 5/2(-2) + b
  • -1 = -5 + b
  • b = 5 - 1
  • b = 4

<u>So the equation is:</u>

  • y = 5/2x + 4
3 0
3 years ago
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