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Keith_Richards [23]
4 years ago
14

I need help how to round up to the nearest tenth

Mathematics
1 answer:
Valentin [98]4 years ago
4 0

Answer:

You just take the hundredths place and then round up if its 5 or above. I'll show you some examples.

Step-by-step explanation:

Tenths Rounding:

29.45 rounded is 29.5

25.42 rounded is 25.4

56.48 rounded is 56.5

2.35 rounded is 2.4

You should be able to kinda read through and get the pattern

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The distance between points A and B is 15. The coordinates of point A are (1, 18) and the
wel

Answer:

9 and 27

Step-by-step explanation:

let me know if you want an explanation

6 0
2 years ago
At a farmers' market Saturday, 5/8 of the vegetables sold were green. Of these, 3/4 were string beans. What fraction of the vege
Dennis_Churaev [7]

Answer: 15/32

Step-by-step explanation:

The data that we have is:

5/8 of the vegetable sold where green.

of theses 5/8, 3/4 were string beans.

Then the 3/4 is applied to the 5/8 of green vegetables.

Then the fraction (of the total number of vegetables) that were string beans was:

F  = (3/4)*(5/8) = (3*5)/(4*8) = 15/32

3 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
CosA.cosecA=cotA can you please help me with this
chubhunter [2.5K]

CscA = 1/sinA

CosACscA = cosA × 1/sinA = cosA/SinA = cotA

3 0
3 years ago
What is the approximate scale factor dilating from the red image to the blue image?Explain how you figured this out.
Lorico [155]

If the shape on the red image is scaled to the shape on the blue image, the scale factor is 0.2777.

Explanation:

  • The original shape's base in the red image is measured. The base of the red image is measured to be 9 units. Now we measure the same side of the blue image. The base of the blue image is measured to be 2.5 units. So after scaling, the length of the painting will be 2.5 units.
  • To calculate the scale factor, we divide the measurement after scaling by the same measurement before scaling. In this case, it is the base of both images. So The scale factor = \frac{baselengthbeforescaling}{baselengthafterscaling} = \frac{2.5}{9} = 0.2777.
  • So the red image is dilated by a scale factor of 0.2777 to produce the blue image.

5 0
3 years ago
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