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jekas [21]
2 years ago
12

Review. (a) Show that a magnetic dipole in a uniform magnetic field, displaced from its equilibrium orientation and released, ca

n oscillate as a torsional pendulum (Section 15.5) in simple harmonic motion.
Physics
1 answer:
muminat2 years ago
8 0

The answer is τ is proportional to θ

<h3>What is SHM?</h3>

A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. The French mathematician Joseph Fourier made the discovery that any regularly recurring motion or wave, regardless of how complex its shape, may be thought of as the sum of a collection of straightforward harmonic motions or waves in 1822.

Consider a magnetic dipole that has been liberated from its equilibrium orientation in a homogeneous magnetic field.  Let the angle between the magnetic moment and the magnetic field be θ. The torque on the dipole due

to the external field is, τ=μXB

and magnitude of,     τ=μB sinθ

if the angle is small, then,    τ=μBθ

or,                                          τproportionalθ

which is the equation for a restoring torque, so the dipole tends to turn the dipole toward its equilibrium

orientation if displaced from its original position. So a magnetic dipole in a uniform magnetic field can oscillate as

a torsional pendulum in SHM if displaced from its equilibrium position.

To learn more about SHM, Visit: brainly.com/question/28230148

#SPJ4

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What is the difference between flashing point, boiling point and melting point​
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<h3><u>Answer and explanation;</u></h3>
  • <u>Melting point</u> is defined as the temperature at which solid and liquid phases are in equilibrium. It is the temperature at which a solid changes state from solid to liquid at atmospheric pressure.
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3 years ago
Read 2 more answers
Which of the following materials is necessary to stop an alpha particle? a. three feet of concrete c. single sheet of aluminum f
Nat2105 [25]
A single sheet of paper can stop an alpha particle
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4 years ago
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REDDIT You look at a circular loop of wire such that the plane of the loop is perpendicular to your line of vision. The loop has
sergiy2304 [10]

Answer:

The circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.

Explanation:

Since the magnetic field, B points in my direction and the current, I is moving in a clockwise direction, the current is always perpendicular to the magnetic field and will thus experience a constant force, F = BILsinФ where Ф is the angle between B and L.

Since the magnetic field is in my direction, it is perpendicular to the plane of the circular loop and thus perpendicular to L where L = length of circular loop. Thus Ф = 90° and F = BILsin90° = BIL

According to Fleming's left-hand rule, the fore finger representing the magnetic field, the middle finger represent in the current and the thumb representing the direction of force on the circular loop.

At each point on the circular loop, the force is always directed towards the center of the loop and thus tends to compress it.

<u>So, the circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.</u>

3 0
3 years ago
A pilot claims to have seen a UFO moving initially at a speed of about 351 m/s in an easterly direction and then, in a time inte
serious [3.7K]

Answer:

Explanation:

This problem can be solved easily if we represent velocity in the form of vector.

The velocity of 351 was towards easterly direction so

V₁ = 351 i

The velocity of 351 was towards south west making - 48° with east or + ve x direction.

V₂ = 351 Cos 48 i - 351 sin 48 j

V₂ = 234.86 i - 260.84 j

Change in velocity

= V₂ - V₁ = 234.86 i - 260.84 j - 351 i

= -116.14 i - 260.84 j

acceleration

= change in velocity / time

(-116.14 i - 260.84 j )/ 1

= -116.14 i - 260.84 j

magnitude = 285.53 ms⁻²

Direction

Tan θ = 260.84 / 116.14 = 2.246

θ = 66 degree south of west .

3 0
3 years ago
If a car is moved 10 meters and 3 Newtons of force is needed to move the car, what amount of work has been done?
Bingel [31]

Answer:

Work=30J

Explanation:

Work=F*x

F=3N

x=10m

Work=3*10=30J

3 0
3 years ago
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