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LuckyWell [14K]

3 years ago

8

Which has a larger resistance, a 60 W lightbulb or a 100 W lightbulb? Which has a larger resistance, a 60 W lightbulb or a 100 W

lightbulb? There's not enough information to tell. The 100 W bulb. The 60 W bulb. Their resistances are the same.

1 answer:

Luba_88 [7]3 years ago

5 0

You really can't tell.

Power = I^2 × R = V^2 / R ( unit in Watt)

For P = I^2 × R

Where we have P directly proportional to R, increase in Power leads to increase in R

So if we have 100 will have higher resistance

For P = V^2/R

Power is inversely proportional to resistance.

So increase in Power leads to decrease in resistance.

60 watt will have a higher resistance.

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Rank the wavelengths of the following quantum particles from the largest to the smallest. If any have equal wavelengths, display

goldfiish [28.3K]

The wavelengths of the following quantum particles from the largest to the smallest is (d) > (a) = (e) > (b) > (c)

De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.

De Broglie's relationship is given by $\lambda=\frac{h}{mv}$ .

This can be written as $\lambda=\frac{h}{p}$ .....(1) where λ is known as de Broglie wavelength and p is momentum , h = Plank’s constant .

As we know that mass of proton is greater than electron and photon .

(a)For photon , the momentum is given by $p=\frac{E}{c}$ ...(2) where c is the speed is the speed of light .

Putting E = 3eV in equation (2) , we get

$p=\frac{3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^7Js/m$

Putting this value of p in equation (1) , we get

$\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-27}}\\\lambda=4.13\times10^{-7}$

(b) As we know that kinetic energy is given by

$K.E=\frac{1}{2} mv^2\\\\2K.E = mv^2\\2K.E\times m = m^2v^2\\2K.E\times m = (mv)^2\\2K.E\times m = p^2\\\\\sqrt{2K.E\times m }=p$ ...(3)

Where mass of electron is $9.1\times10^-^3^1 kg$ .

Putting K.E = 3eV in equation (3) , we get

$\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 9.31\times10^{-31} }\\p=\sqrt{89.376\times10^{-50}} \\p=9.45\times10^{-25}Js/m$

Putting this value of p in equation (1) , we get

$\lambda=\frac{6.62\times10^{-34}}{9.45\times10^{-25}}\\\lambda=0.7005\times10^{-9}$

(c) Putting $m=1.67\times10^{-27}kg$ and K.E = 3eV in equation (3) , we get

$\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 1.67\times10^{-27} }\\p=\sqrt{16.032\times10^{-46}} \\p=4.003\times10^{-23}Js/m$

Putting this value of p in equation (1) , we get

$\lambda=\frac{6.62\times10^{-34}}{4.003\times10^{-23}}\\\lambda=1.65\times10^{-11}$

(d) Putting E = 0.3eV in equation (2) , we get

$p=\frac{0.3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^8Js/m$

Putting this value of p in equation (1) , we get

$\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-28}}\\\lambda=4.13\times10^{-6}$

(e) Putting $p=3eV/c$ in equation (1) , we get

$\lambda=\frac{6.62\times10^{-34}\\\times3\times10^8}{3\times1.6\times10^{-19}}\\\lambda=4.13\times10^{-7}$

On comparing the wavelength order should be (d) > (a) = (e) > (b) > (c) .

Learn more about de brogile here :

brainly.com/question/28165547

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6 0

2 years ago

A block is pulled across a table by a constant force of 9.20 N. If the mass of the block is 2.30kg, how fast will the block be m

kaheart [24]

Answer:

$8\:\text{m/s}$

Explanation:

From Newton's 2nd Law, we have $\Sigma F=ma$ . Using this, we can find the acceleration of the object:

$9.20=2.30a,\\a=\frac{9.20}{2.30}=4\:\mathrm{m/s^2}$ .

Now that we've found the block's acceleration, we can use the following kinematics equation to find its final velocity after 2 seconds:

$v_f=v_i+at,\\v_f=0+4(2),\\v_f=\boxed{8\:\text{m/s}}$

*Assumption: The block is initially at rest and has a initial velocity of zero. Otherwise, the question is unsolvable.

5 0

3 years ago

A 50.0-g Super Ball traveling at 25.0 m/s bounces off a brick wall and rebounds at 22.0 m/s. A

Setler [38]

Explanation:

Average acceleration is change in velocity over time.

a = Δv / Δt

a = (22.0 m/s − (-25.0 m/s)) / 0.00350 s

a = 13,400 m/s²

7 0

3 years ago

A man walks 7 km East in 1 hours and then 2.5 km West in 0.5 hour.

Hitman42 [59]

Explanation:

equation is speed=distance/time

so 9.5km/1.5 equals 6.3km/h

8 0

4 years ago

Read 2 more answers

What happens when a boxer doesn't make weight?

ryzh [129]

They would just have to box in a higher weight class

6 0

3 years ago