When positive and negative charges are separated they want to...
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Answer:
The magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.
Explanation:
Given;
length of the straight wire, L = 0.56 m
conventional current, I = 0.4 A
distance of magnetic field from the wire, r = 2.6 cm = 0.026 m
To determine magnitude of magnetic field made by current in the wire, we will apply Bio-Savart Law;
Therefore, the magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.
Answer:
a) High and low pressures are 15.999 kilopascals and 10.666 kilopascals, respectively.
b) High and low pressures are 2.320 pounds per square inch and 1.547 pounds persquare inch, respectively.
c) High and low pressures are 1.632 meters water column and 1.088 meters water column, respectively.
Explanation:
a) <em>High and low pressures in kilopascals</em>:
101.325 kPa equals 760 mm Hg, then, we can obtain the values by a single conversion:
High and low pressures are 15.999 kilopascals and 10.666 kilopascals, respectively.
b) <em>High and low pressures in pounds per square inch</em>:
14.696 psi equals 760 mm Hg, then, we can obtain the values by a single conversion:
High and low pressures are 2.320 pounds per square inch and 1.547 pounds persquare inch, respectively.
c) <em>High and low pressures in meter water column in meters water column</em>:
We can calculate the equivalent water column of a mercury column by the following relation:
(Eq. 1)
Where:
,
- Densities of water and mercury, measured in kilograms per cubic meter.
,
- Heights of water and mercury columns, measured in meters.
If we know that ,
,
and
, then we get that:
High and low pressures are 1.632 meters water column and 1.088 meters water column, respectively.