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wolverine [178]
2 years ago
8

If a rock sample has a mass of 1.17 g and a volume of 0.33 cm3, what type of rock is it? if a rock sample has a mass of 2.7 g an

d a volume of 1.1 cm3, what type of rock is it? if a rock sample has a mass of 11.2 g and a volume of 1.9 cm3, what type of rock is it?
Mathematics
1 answer:
VashaNatasha [74]2 years ago
8 0

The given rock is a diamond because its density ranges among 3.5 and 3.54 g/cm³.

<h3>What is density?</h3>

Density is the mass of a specific material per unit volume. Density is commonly measured in grams per cubic centimetre. Water, for example, has a density of 1 gram per cubic centimetre, whereas Earth has a density of 5.51 grams per cubic centimetre.

  • Density is also measured in kilograms per cubic metre (or metre-kilogram-second or SI units).
  • Air has a density of 1.2 kilograms per cubic metre. Textbooks and handbooks list the densities of popular solids, liquids, and gases.
  • Density provides an easy way to calculate a body's mass from its volume and vice versa; a mass is proportional to the quantity multiplied by density (M = Vd), or the volume is equal to mass divided by the density. (V = M/d).

The formula for density is;

D = M/V,

where,

D is density,

M is mass ( = 1.17 g)

V is volume (0.33 cm³)

Substituting the values in the density formula;

Density = 1.17/0.33

Density = 3.54 g/cm³

As, diamond has a density that ranges between 3.5 & 3.54 g/cm3. As a result, the above rock is indeed a diamond.

To know more about the density, here

brainly.com/question/6838128

#SPJ4

The correct question is-

If a rock sample has a mass of 1.17 g and a volume of 0.33 cm3, what type of rock is it?

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Answer:

P(X \geq 1) =1-P(X

And we can use the probability mass function and we got:

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And replacing we got:

P(X \geq 1) = 1-0.00615 = 0.99385

Step-by-step explanation:

Let X the random variable of interest "number of graduates who enroll in college", on this case we now that:  

X \sim Binom(n=4, p=0.72)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X \geq 1)

And we can use the complement rule and we got:

P(X \geq 1) =1-P(X

And we can use the probability mass function and we got:

P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615

And replacing we got:

P(X \geq 1) = 1-0.00615 = 0.99385

5 0
3 years ago
What is the value of :-<br><br>=》<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20-%204%7D%7B5%20-%205%7D%20" id="TexFormu
Tresset [83]

Answer:

the value is undefined

Step-by-step explanation:

hey there,

->

\frac{4 - 4}{5 - 5}

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4 0
2 years ago
What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?k = a0
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F(x) = 112 - kx
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f(-3) = 112 - k(-3)
f(-3) = 112 + 3k
121 = 112 + 3k
121 - 112 = 3k
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5 0
2 years ago
Read 2 more answers
Please answer all three questions for full points.​
ludmilkaskok [199]

Answer:

Step-by-step explanation:

1. a) vertical stretch by a factor of 5 and

  e) reflection over x-axis

2. c) reflection over the y-axis

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5 0
3 years ago
how long will it take an investment of $300 to triple, if the interest rate is 3.5% per year, compounded continuously?
Rashid [163]

Answer:

31 years to triple the investment

Step-by-step explanation:

Initial investment = 300

Triple amount that is final amount = 300*3= 900

rate of interest = 3.5 % = 0.035

we need to find out number of years (t)

for compounded continuously we use formula

A= Pe^{rt}

A is the final amount

P is the initial amount

r is the rate of interest

t is the number of years

900 = 300e^{0.035*t}

Divide both sides by 300

3 =e^{0.035*t}

take 'ln' on both sides

ln(3) =ln(e^{0.035*t})

ln(3) = 0.035t ln(e)

ln(e)= 1

\frac{ln(3)}{0.035} = t

t= 31.3889

Round to nearest whole number

t= 31 years


4 0
3 years ago
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