How do you solve x^2+4x-5=0
2 answers:
Try this option:
1. root1*root2=-5; root1+root2=-4.
2. root1=-5; root2=1.
answer:1;-5.
Actually the answer is (-1,5)
x^2 – 4x – 5 = 0
x^2 – 4x = 5
x^2 – 4x + 4 = 5 + 4
(x – 2)^2 = 9
x – 2 = ± 3
x = 2 + 3 and x = 2 – 3
x = 5 and x = –1
{–1, 5}
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