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Gennadij [26K]
3 years ago
14

How do you solve x^2+4x-5=0

Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0
Try this option:
1. root1*root2=-5; root1+root2=-4.
2. root1=-5; root2=1.
answer:1;-5.
gizmo_the_mogwai [7]3 years ago
7 0

Actually the answer is (-1,5)


x^2 – 4x – 5 = 0

x^2 – 4x = 5

x^2 – 4x + 4 = 5 + 4

(x – 2)^2 = 9

x – 2 = ± 3

x = 2 + 3 and x = 2 – 3

x = 5 and x = –1

{–1, 5}


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