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iragen [17]
2 years ago
15

Which of the following can be identified from the box plot?

Mathematics
1 answer:
satela [25.4K]2 years ago
5 0

The data that can be identified from the box plot are Minimum and Median

<h3>How to determine the data that can be identified from the box plot?</h3>

The box plot is used to determine the five-number summary

The five-number summaries are:

  • Minimum
  • Lower quartile
  • Median
  • Upper quartile
  • Maximum

From the list of options, we have:

Minimum and Median

Hence, the data that can be identified from the box plot are Minimum and Median

Read more about box plot at

brainly.com/question/3473797

#SPJ1

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Which of the following graphs represents a function choose all that apply
melisa1 [442]

Answer:

where the graphs?

Step-by-step explanation:

4 0
3 years ago
HELP HELP
Liono4ka [1.6K]

Answer:

Equation of the parabola: y = 3 - 7x^2

Step-by-step explanation:

The equation of the parabola with vertex (h,k) is y = a(x - h)^2 + k

Thus, the equation of this parabola is  y = ax^2+3

To find a, use the fact that the parabola passes through the point (1,−4):

-4 = a(1)^2 +3

Solving this equation, we get that a = −7.

Thus, the equation of the parabola is y = 3 − 7x^2.

5 0
3 years ago
Find cos 30 in terms of cos 0
SVETLANKA909090 [29]

Answer:

cos(30) = (sqrt(3)/2) * cos(0)    

Step-by-step explanation:

cos(0) = 1

cos(30) = sqrt(3)/2

Thus, we can write that:

cos(30) = (sqrt(3)/2) * cos(0)

7 0
3 years ago
Quick! I need an answer now! Please!
horsena [70]

this equation is a non linear equation

4 0
2 years ago
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What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
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