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Leni [432]
3 years ago
9

You have 26 cards, each labeled with a letter of the alphabet. What is the probability of drawing a card that contains one of th

e letters in the word 'MATH'?
Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

Answer: you were right it was 2/13 thanks i needed it for my test

Step-by-step explanation:

UNO [17]3 years ago
6 0
4/26 which simplified to 2/13

so 2/13 is the answer
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A restaurant chain wants to change their oil from peanut oil to canola oil in order to save money. However, the restaurant wants
yulyashka [42]

Answer:

yes

Step-by-step explanation:

3 0
4 years ago
Urgent. Factor the trinomial by grouping. Please show work. 14x^2y+9xy^2+y^3. If prime, show how you got prime answer.
ch4aika [34]

Answer:

y x (2x +y) x (7x +y)

Step-by-step explanation:

14x^2y + 9xy^2 +y^3

(Factor the expression)

y x (14x^2 +9xy +y^2)

(Rewrite the expression)

y x (14x^2 + 7xy +2xy +y^2)

(Factor the expression)

y x (7x x(2x +y) + y x (2x +y) )

(Factor the expression)

y x (2x +y) x (7x +y)

:))

3 0
3 years ago
When rolling a number cube what is the probability of rolling a number greater than two
tatyana61 [14]

Answer:

it is 5/6

Step-by-step explanation:

it's easy. There are 5 numbers that are greater than 2.

3 0
4 years ago
Read 2 more answers
The box and whiskers plot shows the weights, in kilograms, of randomly selected packages in a mail truck. Which of the following
GREYUIT [131]

Answer:2

Step-by-step explanation:

8 0
3 years ago
You are considering buying a piece of industrial equipment to automate a part of your production process. This automation will s
Minchanka [31]

Answer:

No.

Step-by-step explanation:

The equipment wll save $35,000 per over for 10 years, which totals to $350,000.

If the equipment is bought on a simple interest rate of 12% annually for ten years, it will cost:

A = P (1 + rt),\\where\ A =\ Final\ amount,\ r=rate\of\interest\annually,\ t=time,\ P= Principal\ value\\\\P = 200,000r = 0.12t = 10 \\\\A = 200,000 ( 1 + 0.12\times 10)\\A = 200,000 (1 + 1.2)\\A = 200,000 (2.2)\\A = 440,000

We will need to pay $440,000 in total for the machine in over ten years.

If we compare both values, it can be deduced that industrial equipment is more expensive than labor cost.

4 0
3 years ago
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