All categories

2 years ago

Help me please 8th grade khan academy virticle angles

Mathematics

1 answer:

ivanzaharov [21]2 years ago

8 0

The answer is 62^ it reflects angle IK

You might be interested in

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

6 0

3 years ago

Please help me. I don’t know how to do this I really need this answer.

Ainat [17]

The answer is c.
I will explain

p - 2r = q

1. Move variable to the right by adding it’s opposites on both sides

p - 2r + 2r = q + 2r

2. Eliminate the opposites (-2r and +2r)

p = q + 2r

8 0

3 years ago

PLEASE HELP, WILL GIVE BRAINLIEST!!!<br><br><br> Find the inverse of f(x)=6x-4<br> and find f^-1(62)

Lena [83]

Answer: 11

=========================

Explanation:

To find the inverse, or f^-1 of a function, you first replace the y= 6x-4 with x=6y-4

Finding the inverse from here is basically just finding y in terms of x.

1) x=6y-4
2) x+4=6
3) (x+4)/6= y

y= (x+4)/6 is now your f^-1.

Now that you have your inverse, replace 62 with your x in y=(x+4)/6

1) (62+4)/6
2) 66/6
3) 11

Therefore, f^-1(62)= 11

Hope this helps :)

5 0

2 years ago

Read 2 more answers

Greatest common factor of the following monomials 40a^3b and 24a^3b^5

timofeeve [1]

the gcf is product of gcf each factor,

gcf(40a³b,24a³b⁵)

= gcf(40,24)•gcf(a³,a³)•gcf(b,b⁵)

= 8a³b

8 0

3 years ago

PLS HELP

prohojiy [21]

Answer:

Last option

Step-by-step explanation:

7 0

3 years ago