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Vikki [24]
3 years ago
14

Simplify.Your answer should contain only positive exponents.(x^3y^-2)-4

Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0
X^3(1/y^2)-4 is (x^3y^-2)-4 simplified with only positive exponents
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your long distance telephone provider offers two plans, Plan A has a monthly fee of $15 and $0.25 per minute. Plan B has a month
Nitella [24]
Plan A:

15+(0.25x)

15+(0.25×80)

15+(20)

35

Plan B:

20+(0.05x)

20+(0.05×300)

20+(15)

35

I am sure there are other numbers that you can use but I just choose the number 35! Good luck!
6 0
3 years ago
What are the zeros of the polynomial function f(x)=x^3-x^2-12x
Ostrovityanka [42]

Answer:

{0, 4 and -3}

Step-by-step explanation:

f(x)=x^3-x^2-12x can be factored, starting by taking out the 'x' factor:

f(x)=x^3-x^2-12x = x(x^2 - x - 12), and then by factoring the quadratic:

f(x) = x(x - 4)(x + 3) = 0

Then the zeros are {0, 4 and -3}.

7 0
3 years ago
Read 2 more answers
If w and are numbers, which of the following expressions will always be the distance between w and Q
aev [14]
<h3>Answer: Choice A.  |w - q|</h3>

Let's say for example that w = 10 and q = 7. This means the distance between these values is w-q = 10-7 = 3. This is the distance between w and q.

Now let's make q larger. If w = 12 and q = 20, then w-q = 12-20 = -8 assuming we subtract in the same order. We use absolute value bars to ensure the result is positive. So instead we say

|w - q| = |12 - 20| = | -8 | = 8

Distance is never negative.

3 0
4 years ago
Will give Brainlyst pic included
aleksley [76]

Answer

The answer to this problem is a

Step-by-step explanation:

You times 6 x 6 then add 2 ad minus that from 64 then thats the answer

6 0
3 years ago
The units of the subway map below are in miles. Suppose the routes between stations are straight, find the distance you would tr
Nat2105 [25]

Answer:

4.5 miles

Step-by-step explanation:

On the graph,

  • Elm station is located at (-3,-6)
  • Oak station is located at (-1,-2)

We use the distance formula to find the distance between Elm and Oak.

\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\(x_1,y_1)=(-3,-6), (x_2,y_2)=(-1,-2)\\Distance=\sqrt{(-1-(-3))^2+((-2)-(-6))^2} \\=\sqrt{(-1+3)^2+(-2+6)^2} \\=\sqrt{2^2+4^2}\\=\sqrt{20}$ Units \\ Distance =4.5 mile (to the nearest tenth of a mile.)

4 0
4 years ago
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