Identify the domain of the function shown in the graph.
1 answer:
Answer:
D.
Step-by-step explanation:
In order to answer this question we need to know the definition of the domain. The domain of a function is the complete set of possible values of the independent variable ("x"). In our case we can look at the function and cross out option "A" because the function has no point with a negative "x" value. Option "B" can be also crossed out because it states that "x" values can not go above 3 but by looking at the function we can see multiple point with "x" values larger then 3. Option "C" can also be crossed out because their is not point on the function that would have a negative "x" value which contradicts the statement about all numbers. And finally we are left with "D" and we know it is the right answer since the function has a point with "x" value being equal to 0 and the all other points have the "x" value greater then 0, which is exactly what option "D" states.
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Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>
Step-by-step explanation:
The equation can be solved by squaring both sides:
We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:
The square root of 49 equals 7, but the square root of -1 is an imaginary number.
The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>
We are given
Ronaldo delivers the papers at the rate of 6 papers in 24 minutes
so, number of papers =6 in time =24 minutes
so, firstly we can find rate
rate = ( number of papers)/( time taken)
now, we can find times
Time for 56 papers:
we are given
number of papers =56
rate is
now, we can find time
Time for 41 papers:
we are given
number of papers =41
rate is
now, we can find time
now, we can find time difference
so, we can plug values
..............Answer
Answer:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
Step-by-step explanation:
We can demonstrate that Circle R is similar to Circle Q by translating the center of the former one to the center of latter one. Meaning that every point of circle R experiments the same translation. Vectorially speaking, a translation is defined by:
(1)
Where:
- Original point.
- Translated point.
- Translation vector.
If we know that and
, then the translation vector is:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
