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Artist 52 [7]
4 years ago
13

Select the proper order from least to greatest for 2⁄3 , 7⁄6 , 1⁄8 , 9⁄10 . A. 2⁄3 , 9⁄10 , 7⁄6 , 1⁄8 . B. 1⁄8 , 9⁄10 , 7⁄6 , 2⁄

3 . C. 7⁄6 , 9⁄10 , 2⁄3 , 1⁄8 . D. 1⁄8 , 2⁄3 , 9⁄10 , 7⁄6 .
Mathematics
2 answers:
Contact [7]4 years ago
5 0
Know this?  Add apples to apples and oranges to oranges.
This problem becomes much easier if the fractions are converted to decimal fractions for comparison purposes:

<span>2⁄3 , 7⁄6 , 1⁄8 , 9⁄10
are approx equal to 0.67, 1.17, 0.125, 0.90

So, rearranging these numbers in increasing order, we get 

0.125, 0.67, 0.90, 1.17.

We could go back to the originals:   1/8, 2/3, 9/10, 7/6.</span>
saul85 [17]4 years ago
3 0
I believe that D is right hope this helps
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Please help <br> -3.7n = -22.2
nevsk [136]

Answer:

n=-22.2/-3.7 { - and - will cancel}

so n=22.2/3.7

therefore n=6

5 0
3 years ago
PLEASE ANSWER ILL MARK BRAINLIEST!!! (30 POINTSS) The swimming pool at Spring Valley High School is a rectangle with a width of
Step2247 [10]

Answer:

You could try to do it side by side then the area x side.

Step-by-step explanation:

Sorry if it is not much help, hope you figure it out!

8 0
2 years ago
17. Solve for w: P = 21 + 2w​
Viktor [21]

Answer:

w = -10.5

Step-by-step explanation:

p = 21 +2w

get 2w by its self

p= 21 + 2x

-21  -21

p - 21 = 2w

cancel out p

p(0) - 21 = 2w

-21 = 2w

divide both sides by 2

w= -10.5

Hope this helps!!!

5 0
3 years ago
1. In how many different ways can 5 people be seated at a round table?
Alexeev081 [22]
1. 

Assume the people A, B, C, D and E are sitting in a row.

since there are 5 positions, they can sit in 5*4*3*2*1=120 ways.

consider 1 certain sitting position, for example ABCDE, that is B has A to his right, C to his left. D has C to his right and E to his left. And so on.

the positions 

ABCDE
BCDEA
CDEAB
DEABC
EABCD

while in a row are different positions, in a round table they are the same thing.

(read the letters starting from A, and when the letters finish, continue reading from the beginning of the row. They all read "ABCDE")

This means that any arrangement in a round table, is converted to 5 arrangements in a row.

So there are in total  \frac{5!}{5}=4*3*2*1=24 arrangements of 5 people around a table.

2. check picture.

Consider the case where A is at (2, 2) and B is at (5, 6)

A can move to B through 3 horizontal units to the right, we call them E (for East) and 4 vertical units up, which we call N (for north).

the total path is 7 units.

it can be done in several ways, for example:

ENNNENE (the red path shown in the figure)
NNEEENN (the black path shown in the figure)

In total there are 
\frac{7!}{3!*4!}= \frac{7*6*5*4!}{3!*4!}= \frac{7*6*5}{3!}= 35 paths.

Remark: 7! is the number of arrangements if the letters were different. We divide by 3! because of the 3 E's and 4! because of the 4 N's. 

Another possibility could be A'(3, -5), B'(8,-3).

From A' to B' we go by a total of 5 E and 2 N, so there are 

\frac{7!}{2!*5!}= \frac{7*6*5!}{2!*5!}= \frac{7*6}{2}= 42 paths in total.
there is one more possibility
\frac{7!}{1!(6!)}=7

C.

a) consider the letters {V,E,C,T,O,R}

we can form 6*5*4*3*2*1=720 words, as the first digit can be any of the 6 letters, combined with 5 for the second letter and so on.

b) the difference with a is that we have 5 letters and we have 2 T.

we have in total 5*4*3*2*1=120 arrangements of these letters, if the 2 T's were considered as separate.

consider the arrangements:

T_1RUST_2 and T_2RUST_1.

We read bth as just TRUST, but the permutation formula 5*4*3*2*1 considers these as 2 different.

this is why we need to divide 120 by 2, to get the actual number of words that can be formed. So the number is 60.

Answers:

1) 24

2) 7, 35 or 42. it depends on the positions of A and B, check the solution

3) a-720, b-160
 

8 0
4 years ago
The CPI for 1930 was 16.7, while for 1939 it was 13.9. If an item costs $100 in 1930, how much would it have cost in 1939?
Goshia [24]

Answer:

<h2>$83.2</h2>

Step-by-step explanation:

If the CPI for 1930 was 16.7, while for 1939 it was 13.9, the change in CPI will be 16.7 - 13.9 = 2.8. The amount lost within the year 19.30 to 1939 if the cost of the item in 1930 is $100 will be expressed as;

= 2.8/16.7 * 100

= 280/16.7

= $16.8

The amount the item would have cost in 1939 will be $100 - $16.8 = $83.2

5 0
3 years ago
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