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Artist 52 [7]
3 years ago
13

Select the proper order from least to greatest for 2⁄3 , 7⁄6 , 1⁄8 , 9⁄10 . A. 2⁄3 , 9⁄10 , 7⁄6 , 1⁄8 . B. 1⁄8 , 9⁄10 , 7⁄6 , 2⁄

3 . C. 7⁄6 , 9⁄10 , 2⁄3 , 1⁄8 . D. 1⁄8 , 2⁄3 , 9⁄10 , 7⁄6 .
Mathematics
2 answers:
Contact [7]3 years ago
5 0
Know this?  Add apples to apples and oranges to oranges.
This problem becomes much easier if the fractions are converted to decimal fractions for comparison purposes:

<span>2⁄3 , 7⁄6 , 1⁄8 , 9⁄10
are approx equal to 0.67, 1.17, 0.125, 0.90

So, rearranging these numbers in increasing order, we get 

0.125, 0.67, 0.90, 1.17.

We could go back to the originals:   1/8, 2/3, 9/10, 7/6.</span>
saul85 [17]3 years ago
3 0
I believe that D is right hope this helps
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Vadim26 [7]

Answer:

Am I missing something to this question?

As pictured, the answer is 12 7/9ths.

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3 years ago
Define the following terms:
Karolina [17]

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2 years ago
Help with this question please
dimaraw [331]

The answer should be C

4 0
3 years ago
What fraction of the students in the class named baseball their favorite sport
mojhsa [17]

now, let's take a peek at the denominators, we have 3 and 8 and 12, we can get an LCD of 24 from that.

Let's multiply both sides by the LCD of 24, to do away with the denominators.

so, let's recall that a whole is "1", namely 500/500 = 1 = whole, or 5/5 = 1 = whole or 24/24 = 1 = whole.  So the whole class will yield a fraction of 1/1 or just 1.

\bf ~\hspace{7em}\stackrel{\textit{basketball}}{\cfrac{1}{3}}+\stackrel{\textit{soccer}}{\cfrac{1}{8}}+\stackrel{\textit{football}}{\cfrac{5}{12}}+\stackrel{\textit{baseball}}{x}~=~\stackrel{\textit{whole}}{1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{24}}{24\left(\cfrac{1}{3}+\cfrac{1}{8}+\cfrac{5}{12}+x \right)=24(1)}\implies (8)1+(3)1+(2)5+(24)x=24 \\\\\\ 8+3+10+24x=24\implies 21+24x=24\implies 24x=3 \\\\\\ x=\cfrac{3}{24}\implies x=\cfrac{1}{8}

4 0
3 years ago
Question
bekas [8.4K]

Answer:

y=-1/5x-8/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-1))/(2-(-3))

m=(-2+1)/(2+3)

m=-1/5

y-y1=m(x-x1)

y-(-1)=-1/5(x-(-3))

y+1=-1/5(x+3)

y=-1/5x-3/5-1

y=-1/5x-3/5-5/5

y=-1/5x-8/5

7 0
2 years ago
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