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3 years ago

The area of a bookshelf is 216 square inches.If the length of the bookshelf is 36 inches what is the width of the bookshelf?

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

7 0

36÷216=6,so the width of the bookshelf is 6 inches hope this helps:)

yaroslaw [1]3 years ago

6 0

Area = Length x width
216 = 36 x width
width = 216 ÷ 36 = 6 inches

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A number is one thousandth of 78,962. What is the number?

JulsSmile [24]

Answer:

78.962

Step-by-step explanation:

its just moving the decimal

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3 years ago

Simplify the radical expression completely LaTeX: 3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}3 5 − 3 11 + 2 121 − 3 90 A. La

lora16 [44]

Answer:

$3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}$

Step-by-step explanation:

Given

$3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}$

Required

Simplify the expression

$3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}$

Express the square root of 121 as 11

$3\sqrt{5}\:-\:3\sqrt{11}+2 * 11-3\sqrt{90}$

$3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{90}$

Express 90 as 9 * 10

$3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9 * 10}$

Split the surd to 2

$3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9} * \sqrt10}$

Express the square root of 9 as 3

$3\sqrt{5}\:-\:3\sqrt{11}+22-3 * 3 * \sqrt10}$

$3\sqrt{5}\:-\:3\sqrt{11}+22-9 * \sqrt10}$

$3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}$

Hence, the result of the expression is

$3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}$

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3 years ago

Find the value of two numbers if their sum is 12 and their differences is 4

Varvara68 [4.7K]

Answer:

8 and 4

Step-by-step explanation:

You find half of the sum and subtract half of the differece for 6 and the other 6 you add the hal of the difference.

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2 years ago

Read 2 more answers

(2) Janie has 5 purple grapes and 8 red grapes. Select the ratios that compare the number of red grapes to the total number of g

Hitman42 [59]

Answer:

Step-by-step explanation:

Both B and C are right btw. Ratios can be both fractions and in the (x:Y) format.

8 red grapes to 13 total grapes=

8:13 or 8/13

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2 years ago

A small regional carrier accepted 21 reservations for a particular flight with 19 seats. 10 reservations went to regular custome

Viefleur [7K]

We have 19 available seats, and 21 reservations.

Of the 21 reservations, 10 are sure, so we have 10 out of the 19 seats that are surely occupied.

Then, we have 9 seats for 11 reservations, each one with 44% chance of being occupied.

We have to calculate the probability that the plane is overbooked. This means that more than 9 of the reservations arrive.

This can be modelled as a binomial distirbution with n = 11 and p = 0.44, representing the 44% chance.

Then, we have to calculate P(x > 9).

This can be calculated as:

$P(x>9)=P(x=10)+P(x=11)$

and each of the terms can be calculated as:

$\begin{gathered} P(x=10)=\dbinom{11}{10}\cdot0.44^{10}\cdot0.56^1=11\cdot0.0003\cdot0.56=0.0017 \\ P(x=11)=\dbinom{11}{11}\cdot0.44^{11}\cdot0.56^0=1\cdot0.0001\cdot1=0.0001 \end{gathered}$

Then:

$P(x>9)=P(x=10)+P(x=11)=0.0017+0.0001=0.0018$

We have a probability of 0.18% of being overbooked (P = 0.0018).

If we want to calculate the probability of having empty seats, we need to calculate P(x<9), meaning that less than 9 of the reservations arrive.

We can express this as:

$P(x$

We have to calculate P(x=9) as we already have calculated the other two terms:

$P(x=9)=\dbinom{11}{9}\cdot0.44^9\cdot0.56^2=55\cdot0.0006\cdot0.3136=0.0107$

Finally, we can calculate:

$\begin{gathered} P(x$

There is a probability of 0.9875 that there is one or more empty seats.

Answer:

There is a probability of 0.0018 of being overbooked.

There is a probability of 0.9875 of having at least one empty seat.

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10 months ago