I the week starts on Monday he will fill Monday and Saturday and on each Monday he will wash his car
Solution:
Given:
![V=16300(0.94)^t](https://tex.z-dn.net/?f=V%3D16300%280.94%29%5Et)
The value of a car after t - years will depreciate.
Hence, the equation given represents the value after depreciation over t-years.
To get the rate, we compare the equation with the depreciation formula.
![\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3DP%281-r%29%5Et%20%5C%5C%20%5Ctext%7Bwhere%3B%7D%20%5C%5C%20P%5Ctext%7B%20is%20the%20original%20value%7D%20%5C%5C%20r%5Ctext%7B%20is%20the%20rate%7D%20%5C%5C%20t%5Ctext%7B%20is%20the%20time%20%7D%20%5Cend%7Bgathered%7D)
Hence,
![\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\ \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\ \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D16300%280.94%29%5Et%20%5C%5C%20A%3DP%281-r%29%5Et%20%5C%5C%20%20%5C%5C%20%5Ctext%7BComparing%20both%20equations%2C%7D%20%5C%5C%20P%3D16300%20%5C%5C%201-r%3D0.94%20%5C%5C%201-0.94%3Dr%20%5C%5C%20r%3D0.06%20%5C%5C%20To%5Ctext%7B%20percentage%2C%7D%20%5C%5C%20r%3D0.06%5Ctimes100%3D6%5Ctext%7B%20%5C%25%7D%20%5C%5C%20%20%5C%5C%20%5Ctext%7BHence%2C%20%7D%20%5C%5C%20P%5Ctext%7B%20is%20the%20purchase%20price%7D%20%5C%5C%20r%5Ctext%7B%20is%20the%20rate%7D%20%5Cend%7Bgathered%7D)
Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.
(number of yellow marbles) / (overall number of marbles)
=
2/20
The answer to your question is 3