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svetlana [45]
3 years ago
10

Which equation could have been used to create this function table?

Mathematics
1 answer:
ratelena [41]3 years ago
3 0
For multiple-choice questions, it is often faster to check the answers than to try to figure out what the answer should be.

Only selections (A) and (D) match the first entry in the table.
Of those, only selection (A) matches the second entry in the table.

The appropriate choice is ...
   (A) y = x + 9
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(a) If cos² (34°) - sin² (34°) = cos(A°),then<br> A =<br> degree’s
krok68 [10]

~~~~~~~\cos^2 \left(34^{\circ}\right) - \sin^2 \left( 34^{\circ} \right)=\cos A\\\\\implies \cos \left( 2 \cdot 34^{\circ} \right) = \cos A~~~~~~~~~~~~~;[\cos 2x = \cos^2 x -\sin^2 x]\\\\\implies \cos \left(68^{\circ}\right) = \cos A\\\\\implies A = 68^{\circ}

3 0
2 years ago
How to do y=mx+b for the problem 4x-11y=-6
Aleks [24]
Simply rearrange the terms and simplify.

Subtracting 4x from both sides, we have:

-11y=-4x-6

Dividing by -11, we have:

y= \frac{4}{11} \cdot x + \frac{6}{11}

This is in the proper form, so this is our final equation.
6 0
3 years ago
What must 111,111,102 be divided by to get 9 as the quotient and 0 as the remainder?
never [62]
ANSWER: 12,345,678

EXPLANATION:
we can work backwards by figuring out what 9(the answer) is multiplied by to get 111,111,102 (the starting number) we can do this by dividing by 9:

111,111,102/9 = 12,345,678

so: 9 * 12,345,678 = 111,111,102
which also means

111,111,102/12,345,678 = 9 (with 0 as a remainder)

5 0
4 years ago
A study showed that people who take vitamin C daily have a significantly better chance of protecting against a cold than those w
xz_007 [3.2K]
I believe the answer is c
4 0
4 years ago
Find the sq root the sq root of 5 is 2.24
vlada-n [284]

Answer:  \bold{\dfrac{7-3\sqrt5}{2}}

Step-by-step explanation:

You did great until you expanded (3 - √5)².  <em>You forgot the middle term</em>

\dfrac{3-\sqrt5}{3+\sqrt5}\bigg(\dfrac{3-\sqrt5}{3-\sqrt5}\bigg)\\\\\\=\dfrac{(3-\sqrt5)(3-\sqrt5)}{(3+\sqrt5)(3-\sqrt5)}\\\\\\=\dfrac{9-3\sqrt5-3\sqrt5+5}{9-3\sqrt5+3\sqrt5-5}\\\\\\=\dfrac{14-6\sqrt5}{4}\\\\\\\text{Factor out a 2 from the numerator and denominator}\\=\dfrac{2(7-3\sqrt5)}{2(2)}\\\\\\=\large\boxed{\dfrac{7-3\sqrt5}{2}}

6 0
3 years ago
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