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lakkis [162]
3 years ago
12

Find A={a,b,c} then find A*A.​

Mathematics
2 answers:
Alenkasestr [34]3 years ago
7 0

Assuming you want to do a cartesian product, then you basically form items (x,y)  such that x is in set A, and y is in set A

More generally, A * B will consist of items of the form (x,y) such that x is in A and y is in B. However, we have B = A.

So,

A * A = {

(a,a), (a,b), (a,c)

(b,a), (b,b), (b,c)

(c,a), (c,b), (c,c)

}

I broke things up into separate rows to show that we can form a 3x3 table. Each row is a different x value from the set {a,b,c}. Each column is a different y value from the set {a,b,c}

In my opinion, this helps organize things much better than rather have it all on one single line like this

A * A = { (a,a), (a,b), (a,c), (b,a), (b,b), (b,c), (c,a), (c,b), (c,c) }

which in all honesty looks like a bit of a cluttered mess.

Mice21 [21]3 years ago
6 0

Answer:

Step-by-step explanation:

A={a,b,c}

A×A={a×a,a×b,a×c,b×a,b×b,b×c,c×a,c×b,c×c}

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If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), w
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The value of a is 80

Step-by-step explanation:

The distance of a point (x_0,y_0) from the y-axis can be written as

d_y = |x_0|

because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point (x_0,y_0) from the x-axis can be written as

d_x=|y_0|

Since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

d_A = |-30|=30

- The distance of point B (a,a) from the x-axis can be written as

d_B = |a| = a

Since a>0.

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

\frac{2}{3}d_A = \frac{1}{4}d_B

Therefore,

\frac{2}{3}(30)=\frac{1}{4}a

And solving for a,

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Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

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